<span>EP (potential energy) = mgy -> (59)(9.8)(-5) = -2,891
EP + EK (kinetic energy) = 0; but rearranging it for EK makes it EK = -EP, such that EK = 2891 when plugged in.
EK = 0.5mv^2, but can also be v = sqrt(2EK/m).
Plugging that in for sqrt((2 * 2891)/59), we get 9.9 m/s^2 with respect to significant figures.</span>
m/s^2 is 39.2266
is the answer If thats what you needed
Answer:
Its length is measured to be 0.5 m
Explanation:
From theory of relativity (mass variation), we know that:
m = mo/√(1-v²/c²)
Where, m = relative mass
and, mo = rest mass
The momentum of stick while moving, will be:
P = mv
but, it is given in the form of rest mass as:
P = 2(mo)v
thus, by comparison;
2(mo)v = mv
using value of m from theory of relativity;
2(mo)v = (mo)v/√(1-v²/c²)
√(1-v²/c²) = 1/2 ______ eqn(1)
Now, for relativistic length (L), we have the formula from same theory of relativity;
L = (Lo)√(1-v²/c²)
The rest length (Lo) of meter stick is 1 m, and the remaining term on right side √(1-v²/c²), known as Lorentz Factor, can be given by eqn (1), as equal to 1/2.
Thus,
L = (1 m)(1/2)
<u>L = 0.5 m</u>
When you know both the speed and direction of an object’s motion, you know the velocity of an object. speed in a given direction is called velocity
hope this helps :)
