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umka21 [38]
3 years ago
14

What role does the environment play in defining the appearance of an organism? 

Physics
2 answers:
forsale [732]3 years ago
7 0
An organism naturally adapts to it's environment. Organisms have to adapt to survive to live in a certain environment. Their outside appearance and physical features depends on how they get their food, how they protect themselves from predators, and how they keep their body warm or cold in that climate. This kind of goes with the idea of natural selection. Natural selection is when animals adapt to changes over time by reproducing and creating genetic variations in their offspring. For example, if there are two types of rabbits. One rabbit is black and the other is white. These rabbits live in a very cold place where there is a lot of snow. The predators have been eating most of the black rabbits since, they are easily seen. The white rabbits will keep on reproducing, while the black rabbits population will decrease. After a while the black rabbits will be no more and a new generation of white rabbits will be able to survive and thrive.
Sholpan [36]3 years ago
6 0
An organism grows to its environment, also known as adaptation. Organisms will adapt to their surroundings for survival. For example some paramecium is a small single celled fresh water animal, they are covered in cilia so that they could move through the pond water more effectively. Hope this helps. 
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Calculate delta g for the reaction if the partial pressures of the initial mixture are pcl5 = .0029 atm, pcl3 = .27 atm, and pcl
AnnyKZ [126]

Answer: equation for the reaction is given below

PCL2+PCL3=PCL5

Where pcl2=0.40atm,pcl3=0.27atm

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Using ∆G=-RTin(PCL5/PCl2*PCL3)

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Explanation:

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A flea jumps straight up to a maximum height of 0.400 m . what is its initial velocity v0 as it leaves the ground?
timama [110]

For an object`s motion, the Kinematic equation is,

v^2=v_{0}^2+2ah

Here, v is the final velocity and h is stands for the height of the object and a is the acceleration of the object.

As according to question,

v=0m/s,a=g-9.8 m/s^2 and h = 0.400 m

Thus, putting these values in above equation, we get

0= v_{0}^2 -2gh

or

v_{0} =\sqrt{2 \times 9.8 \times 0.400 }

v_{0} = 2.8 m/s

Therefore, initial velocity is 2.8 m/s



8 0
3 years ago
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