A 2300 kg truck has put its front bumper against the rear bumper of a 2500 kg suv to give it a push. with the engine at full pow er and good tires on good pavement, the maximum forward force on the truck is 18,000 n.
2 answers:
Answer:
Acceleration = a = 3.75 m/s^2
Explanation:
Mass of truck1 = m1 = 2300 kg
Mass of truck2 = m2 = 2500 kg
Total mass = m = m1 + m2 = 2300 + 2500 = 4800 kg
Force exerted by truck1 = F = 18000 N
As both trucks are joint together so, behaving as single object. The acceleration can be found by Newton’s second law of motion.
F = ma
a = F/m = 18000/4800
a = 3.75 m/s^2
F=ma
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