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cluponka [151]
4 years ago
15

What value must q2 have if the electric potential at point a is to be zero?

Physics
1 answer:
Ulleksa [173]4 years ago
5 0
 <span>let r be side of square 
V (B) = k q2/r + k Q / sqrt[r^2 + r^2] = 0 given 
q2/r + Q / r root2 = 0 
q2 = - Q / root2 
q2/Q = - 1/root2 
q2/Q = - root2 /2 = - 0.707 

q2 equals negative 0.707 times Q</span>
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Answer:

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3 years ago
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A cube made out of wood has a mass of 1.2 kg and the density of the wood is 400kg/m3.What is the length of the side of the cube?
LenaWriter [7]

Answer:

≈ 0.144 m

Explanation:

Density is mass divided by volume:

D = M / V

Solving for volume:

V = M / D

Given M = 1.2 kg and D = 400 kg/m³:

V = 1.2 kg / (400 kg/m³)

V = 0.003 m³

Volume of a cube is the side length cubed:

V = s³

Therefore:

s³ = 0.003 m³

s ≈ 0.144 m

Round as needed.

5 0
3 years ago
In April 1974, Steve Prefontaine completed a 10 km race in a time of 27 min, 43.6 s. Suppose "Pre" was at the 8.13 km mark at a
SOVA2 [1]

Answer:0.084 m/s^2

Explanation:

Given

Total time=27 min 43.6 s=1663.6 s

total distance=10 km

Initial distance d_1=8.13 km

time taken=25 min =1500 s

initial speed v_1=\frac{8.13\times 1000}{25\times 60}=5.6 m/s

after 8.13 km mark steve started to accelerate

speed after 60 s

v_2=v_1+at

v_2=5.6+a\times 60

distance traveled in 60 sec

d_2=v_1\times 60+\frac{a60^2}{2}

d_2=336+1800 a

time taken in last part of journey

t_3=1663.6-1560=103.6 s

distance traveled in this time

d_3=v_2\times t_3

d_3=\left ( 5.6+a\times 60\right )103.6

and total distance=d_1+d_2+d_3

10000=8.13\times 1000+336+1800 a+\left ( 5.6+a\times 60\right )103.6

1870=336+1800 a+\left ( 5.6+a\times 60\right )103.6

a=0.084 m/s^2

5 0
4 years ago
What does the earths core do
cestrela7 [59]

Answer: Earth scientists have theorized that the Earth's core is responsible for the planet's magnetic field as well as plate tectonics.

Explanation:

6 0
3 years ago
A jet airplane is in level flight. The mass of the airplane is m=8950 kg. The airplane travels at a constant speed around a circ
Mice21 [21]

Answer:

The net force is 91780.8 N.

Explanation:

mass, m = 8950 kg

Radius, R = 9.33 miles = 15015.2 m

Time, T = 0.123 h = 442.8 s

There are two forces acting on the plane.

Horizontal force is the centripetal force and the vertical force is the weight.

Fx =m R w^2\\\\Fx = m R \frac{4\pi^2}{T^2}\\\\Fx = 8950\times 15015.2\times \frac{4\times 3.14\times 3.14}{442.8\times 442.8}\\\\Fx = 27030.8 N \\\\Fy = m g \\\\ Fy = 8950\times 9.8 \\\\Fy = 87710 N

The net force is

F = \sqrt{Fx^2 + Fy^2}\\\\F = \sqrt {27030.8^2 + 87710^2}\\\\F = 91780.8 N

7 0
3 years ago
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