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Pani-rosa [81]
3 years ago
13

I just need the answer to number 1 (with work please) (Newton’s Second Law)

Physics
1 answer:
Valentin [98]3 years ago
8 0

Answer:

wish I could help

Explanation:

I been rereading this and I can't solve it lemme go ask people in ma house real quick

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Mohs scale is used in describing which characteristic? luster toughness hardness crystal form
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The answer is hardness not luster 

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How many neutrons does element X have if it’s atomic number is 28 and it’s mass number is 81?
labwork [276]

Well let’s put it this way. To find the neutrons you subtract the atomic atomic Nuremberg from the atomic mass. So

Mass=81-Number=28

81-28=53

Final answer is 53.

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3 years ago
. A child drops a ball from a window. The ball strikes the ground in 3.0 seconds. What is the. A child drops a ball from a windo
Vsevolod [243]

Answer:

30m/s

Explanation:

  • Use formula for height calculation: Time = √2h/√g
  • From here calculate height which comes out to be: 45m(if g is taken 10)
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3 years ago
Peter’s body supplies a force of 500 N to run up a 10-m hill in 10 s. How much power is involved in Peter’s run up the hill? Exp
shutvik [7]

Answer: 500 Watts

Explanation:

Power P is the speed with which work W is done. Its unit is Watts (W), being 1 W=\frac{1 Joule}{1 s}.

Power is mathematically expressed as:

P=\frac{W}{t} (1)

Where t is the time during which work W  is performed.

On the other hand, the Work W done by a Force F refers to the release of potential energy from a body that is moved by the application of that force to overcome a resistance along a path.  It is a scalar magnitude, and its unit in the International System of Units is the Joule (like energy). Therefore, 1 Joule is the work done by a force of 1 Newton when moving an object, in the direction of the force, along 1 meter (1J=(1N)(1m)=Nm  ).

When the applied force is constant and the direction of the force and the direction of the movement are parallel, the equation to calculate it is:  

W=(F)(d) (2)

In this case, we have the following data:

F=500 N

d=10 m

t=10 s

So, let's calculate the work done by Peter and then find how much power is involved:

From (2):

W=(500 N)(10 m) (3)

W=5000 J (4)

Substituting (4) in (1):

P=\frac{5000 J}{10 s} (5)

Finally:

P=500 W

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3 years ago
A cave explorer travels 3.00 m eastward, then 6.50 m northward, and finally 12.0 m westward. Find the magnitude of the net displ
mina [271]
<span>3 meters east and 15 meters west evens out to 12 meters west. the answer is 12 meters west
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