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Mazyrski [523]
4 years ago
6

What is the mass, in grams, of 28.42 mL of acetone?

Chemistry
2 answers:
NNADVOKAT [17]4 years ago
7 0
V = 28,42 mL = 0,02 L
molar mass C3H6O = 58


n C3H6O
= V / 22,4
= 0,02 / 22,4
= 0,0009 mol


mass
= n x molar mass
= 0,0009 x 58
= 0,0522 gr
elixir [45]4 years ago
4 0

Answer:

22.48 grams.

Explanation:

In order to calculate this you just need to remember the formula for the density of materials, the density of Acetone is: 0.791 g/mL

So in order to calculte the mass we just use the next formula:

Density= mass/volume

Remember that mililiters is a unit for vulome:

Mass= Volume*density

We insert the values:

28.42*0.791ml=22.48 grams

So the mass og 28.42 mililiters of acetone will be 22.48 grams

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Calculate the ph at of a solution of sodium hypochlorite . note that hypochlorous acid is a weak acid with a of . round your ans
loris [4]

The question is incomplete, here is the complete question:

Calculate the pH at 25°C of a 0.39 M solution of sodium hypochlorite NaClO. Note that hypochlorous acid HClO is a weak acid with a pKa of 7.50. Round your answer to 1 decimal place.

<u>Answer:</u> The pH of the solution is 10.4

<u>Explanation:</u>

We are given:

Molarity of sodium hypochlorite = 0.39 M

pK_a of HClO = 7.50

We know that:

pK_a=-\log K_a

K_a  of HClO = 10^{-7.50}=3.16\times 10^{-8}

To calculate the base dissociation constant for the given acid dissociation constant, we use the equation:

K_w=K_b\times K_a

where,

K_w = Ionic product of water = 10^{-14}

K_a = Acid dissociation constant  = 3.16\times 10^{-8}

K_b = Base dissociation constant

Putting values in above equation, we get:

10^{-14}=3.16\times 10^{-8}\times K_b\\\\K_b=\frac{10^{-14}}{3.16\times 10^{-8}}=3.16\times 10^{-7}

The chemical equation for the reaction of hypochlorite ion with water follows:

                    ClO^-+H_2O\rightarrow HClO+OH^-

<u>Initial:</u>           0.39

<u>At eqllm:</u>      0.39-x                   x           x

The expression of K_b for above equation follows:

K_b=\frac{[HClO][OH^-]}{[ClO^-]}

Putting values in above equation, we get:

3.16\times 10^{-7}=\frac{x\times x}{(0.39-x)}\\\\x=-0.00035,0.00035

Neglecting the negative value of 'x' because concentration cannot be negative

To calculate the pOH of the solution, we use the equation:

pOH=-\log[OH^-]

We are given:

[OH^-]=0.00035M

Putting values in above equation, we get:

pOH=-\log (0.00035)=3.6

To calculate pH of the solution, we use the equation:

pH+pOH=14\\pH=14-3.6=10.4

Hence, the pH of the solution is 10.4

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3 years ago
Which of the following is an electrolyte?. A) potassium chloride. B) glucose. C) water D) mayonnaise.
kenny6666 [7]
Answer A )

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K+   Cl-

hope this helps!.
8 0
3 years ago
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