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77julia77 [94]
4 years ago
14

The highest surface wind speeds occur when there is a

Physics
1 answer:
MA_775_DIABLO [31]4 years ago
8 0
The correct answer to the question above is 20 millibar pressure difference between two near locations. The highest surface winds speed occur when there is a 2- millibar pressure difference between two nearby locations. Wind speed or also called as wind velocity is caused by the higher air pressure going to low.
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Fossil fuels currently account for the majority of the world’s energy use because they are A. renewable energy resources. B. dis
Elan Coil [88]
The answer to your question will be C. because they are very inexpensive and are readily available but they will eventually deplete because we use them faster than they can be produced we use what has been building up.
7 0
3 years ago
The acceleration due to gravity on Jupiter is 23.1 m/s2, which is about twice the acceleration due to gravity on Neptune.
polet [3.4K]

Answer:

I believe its C

Explanation:

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3 years ago
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An instrument is defective for all of the following conditions EXCEPT:_______
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Answer:

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4 years ago
If a net horizontal force of 7.5 N is applied to a baby carriage whose mass is 12.5 kg what acceleration is
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Answer:

<h2>0.6 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m} \\

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From the question we have

a =  \frac{7.5}{12.5}  \\

We have the final answer as

<h3>0.6 m/s²</h3>

Hope this helps you

8 0
3 years ago
A solid cylinder is released from the top of an inclined plane of height 0.50 m. From what height, in meters, on the incline sho
dangina [55]

Answer:

Explanation:

for rolling motion down the plane acceleration is given by the following expression

a = g sinθ / (1 + k² / R²)

here k is radius of gyration and R is radius of the object rolling down .

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so k² = R² / 2

k² / R² = 1/2

a = g sinθ /( 1 + 1 / 2 )

= 2 / 3 x  g sinθ

v = √ 2 a s

= √ (2 x  2 / 3 x  g sinθ s )

= √ (4  / 3 x  g h  )

= √ (4  / 3 x  g x .5  )

= √ 2g / 3

for sphere  I = 2/5  m R²

so k² = 2/5 R²

k² / R² = 2 / 5  

a = g sinθ / (1 + 2 / 5)  

= 5 / 7  x  g sinθ

v = √ 2 a s

= √ (2 x  5 / 7  x  g sinθ s )

= √ (10/7  x  g h  )

Given

√ (10/7  x  g h  ) = √ 2g / 3

10/7  x  g h  = 2g / 3

h = 14 / 30 m

= .47 m .

5 0
3 years ago
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