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gogolik [260]
3 years ago
14

What is the equivalent resistance for a series circuit with three resistors: 19.2 ohms, 24.6 ohms, and 31.2 ohms?

Physics
2 answers:
navik [9.2K]3 years ago
5 0
The answer would be 75 ohms
Talja [164]3 years ago
5 0

Answer : The equivalent resistance for a series circuit is 75.0\Omega

Explanation :

Equivalent resistance : It represents the total effect of all resistors in the circuit.

In series circuit, we add all the resistances of each component.

R=R_1+R_2+R_3....

In parallel circuit, the reciprocal of the total resistance is equal to the sum of the reciprocals of the resistances of each component.

\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}...

As we are given:

R_1=19.2\Omega

R_2=24.6\Omega

R_3=31.2\Omega

Now we have to calculate the equivalent resistance for a series circuit.

R=R_1+R_2+R_3

R=19.2\Omega+24.6\Omega+31.2\Omega

R=75.0\Omega

Therefore, the equivalent resistance for a series circuit is 75.0\Omega

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Use 4 to 5 complete sentences, explain the concepts of beats and how beats are produces.
Wewaii [24]

Answer:

Beats is a phenomenon which occurs when two sound waves with different frequencies overlap each other.

Explanation:

When these two sound waves overlap, a third frequency is formed. The places where the two waves reinforces each other, constructive interference takes place and a louder sound is produced whereas, at points where destructive interference takes place a softer sound is produced.

These alternative loud and soft sounds are called beats.

3 0
4 years ago
A 6.20 g bullet moving at 929 m/s strikes a 850 g wooden block at rest on a frictionless surface. The bullet emerges, traveling
nekit [7.7K]

Answer:

(a) Final speed of block = 3.2896 m/s

(b) 6.7350 m/s is the speed of the bullet-block center of mass?

Explanation:

Given that:

Mass of bullet (m₁) = 6.20 g

Initial Speed of bullet (u₁) = 929 m/s

Final speed of bullet (v₁) = 478 m/s

Mass of wooden block (m₂) = 850g

Initial speed of block initial (u₂) = 0  m/s

Final speed of block (v₂) = ?

<u>By the law of conservation of momentum  as:</u>

<u>m₁×u₁ + m₂×u₂ = m₁×v₁ + m₂×v₂</u>

6.20×929 + 850×0 = 6.20×478 + 850×v₂

Solving for v₂, we get:

<u>v₂ = 3.2896 m/s</u>

Let the V be the speed of the bullet-block center of mass. So,

V = [m₁* u₁]/[m₁ + m₂]  (p before collision = p after collision)

   = [6.2 *929]/[5.2+850]

<u>V = 6.7350 m/s </u>

7 0
3 years ago
A lightweight string is wrapped several times around the rim of a small hoop. If the free end of the string is held in place and
MariettaO [177]

Answer:

Explanation:

Let T be the tension

For linear motion of hoop downwards

mg -T = ma , m is mass of the hoop . a is linear acceleration of CG of hoop .

For rotational motion of hoop

Torque by tension

T x R ,      R is radius of hoop.

Angular acceleration be α,

Linear acceleration a = α R

So TR = I  α

= I  a / R

a = TR² / I

Putting this value in earlier relation

mg -T = m TR² / I

mg = T ( 1 + m R² / I )

T = mg / ( 1 + m R² / I )

mg / ( 1 + R² / k² )

Tension is less than mg or weight because denominator of the expression is more than 1.

5 0
3 years ago
Vector A has magnitude 13.0 m and vector B has magnitude 16.0 m. The scalar product A.B is 116 m2. What is the magnitude of the
Elan Coil [88]

Answer:

\text{Vector product}=172.66\ m^2

Explanation:

Given that,

The magnitude of vector A, |A|=13\ m

The magnitude of vector B, |B|=16\ m

Scalar product of A and B, A{\cdot} B=116\ m^2

The formula for the scalar product is given by :

A{\cdot} B=|A||B|\cos\theta

Where, \theta is the angle between A and B.

\cos\theta=\dfrac{116}{13\times 16}\\\\\theta=\cos^{-1}\left(0.5576\right)\\\\\theta=56.11^{\circ}

The formula for the vector product is given by :

A\times B=|A||B|\sin\theta\\\\=13\times 16\times \sin56.11\\\\=172.66\ m^2

So, the vector product between these two vectors is 172.66\ m^2.

6 0
3 years ago
Object A of mass M is released from height H, whereas object B of mass 0.5M is released from height 2H. What is the ratio of the
skelet666 [1.2K]
My solution. ......................

5 0
3 years ago
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