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gogolik [260]
3 years ago
14

What is the equivalent resistance for a series circuit with three resistors: 19.2 ohms, 24.6 ohms, and 31.2 ohms?

Physics
2 answers:
navik [9.2K]3 years ago
5 0
The answer would be 75 ohms
Talja [164]3 years ago
5 0

Answer : The equivalent resistance for a series circuit is 75.0\Omega

Explanation :

Equivalent resistance : It represents the total effect of all resistors in the circuit.

In series circuit, we add all the resistances of each component.

R=R_1+R_2+R_3....

In parallel circuit, the reciprocal of the total resistance is equal to the sum of the reciprocals of the resistances of each component.

\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}...

As we are given:

R_1=19.2\Omega

R_2=24.6\Omega

R_3=31.2\Omega

Now we have to calculate the equivalent resistance for a series circuit.

R=R_1+R_2+R_3

R=19.2\Omega+24.6\Omega+31.2\Omega

R=75.0\Omega

Therefore, the equivalent resistance for a series circuit is 75.0\Omega

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What is the equivalent resistance of a circuit that contains four 75.0 resistors connected in parallel with a 100.0 V battery?
zhannawk [14.2K]
To get the total resistance in a parallel circuit, you need to remember that unlike in a series, you do not just merely add the resistances. You need to get the reciprocal first of each resistance and add them together. 

\frac{1}{R_{T}} =  \frac{1}{R_{1}}+\frac{1}{R_{2}}+\frac{1}{R_{3}}... +\frac{1}{R_{n}}

After adding them, you will get the reciprocal again and then compute for the value. The problem says that there are 4 resistors in the circuit that have a resistance of 75.

\frac{1}{R_{T}} = \frac{1}{75}+\frac{1}{75}+\frac{1}{75}+\frac{1}{75}

Add up the numerator and copy the denominator:

\frac{1}{R_{T}} = \frac{4}{75}

Then get the reciprocal to get the total resistance:

R _{T} = \frac{75}{4}  = 18.75

The answer to your question then is A. 18.8.
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