<span>0.310 moles
First, look up the atomic weights of the elements involved.
Atomic weight carbon = 12.0107
Atomic weight hydrogen = 1.00794
Atomic weight sulfur = 32.065
Molar mass (C3H5)2S = 6 * 12.0107 + 10 * 1.00794 + 32.065
= 114.2086 g/mol
Moles (C3H5)2S = 35.4 g / 114.2086 g/mol = 0.309959145 mol
Since there's just one sulfur atom per (C3H5)2S molecule, the number of moles of sulfur will match the number of moles of (C3H5)2S which is 0.310 when rounded to 3 significant digits.</span>
Answer:
C6H12O6 → 2C2H5OH + 2CO2
Explanation:
Glucose is an organic molecule, specifically a sugar, with the formula C612O6 while ethanol is another organic molecule with formula; C2H5OH.
However, as rightly said in this question, ethanol can be got from glucose via a process called fermentation in the presence of a catalyst called YEAST. The balanced equation is as follows:
C6H12O6 → 2C2H5OH + 2CO2
Hey There!
To solve this question remember that 1 mole of ammonia is equal to 17G of ammonia.
Using that, we first multiply 17 by 7 = 24
Then we multiply 7 by .27 = 1.89
Finally, taking those and adding them together gives you the answer...
<u>25.89 grams :)</u>
<u></u>
<u>Have a great day, I hope I helped.</u>
<u></u>
<u>+ Brainliest & Five stars are always appreciated </u>
Answer:
Ocean
Explanation:
97 percent of the water in the world is in the ocean.
The 3 percent of freshwater is located in lakes, streams, glaciers, and can be found underground.
Answer: 2.5 ml of 0.5 M HNO3 is necessary to titrate 25.0 mL of 0.05 M KOH
solution to the endpoint
Explanation:
To calculate the volume of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is KOH.
We are given:
Putting values in above equation, we get:
Thus 2.5 ml of 0.5 M HNO3 is necessary to titrate 25.0 mL of 0.05 M KOH
solution to the endpoint
