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Snezhnost [94]
3 years ago
15

Fossil fuels are:

Chemistry
1 answer:
Scorpion4ik [409]3 years ago
7 0

Answer:

d

Explanation:

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When you place the north pole of one magnet near the south pole of another magnet, they are attracted to one another.

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What is specific heat capacity ​
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<u>A</u>

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What does it mean for a strong base to be in equilibrium?
prisoha [69]

The position of equilibrium lies far to the right, with products being favoured. Hence, option A is correct.

<h3>What is equilibrium?</h3>

Chemical equilibrium is a condition in the course of a reversible chemical reaction in which no net change in the amounts of reactants and products occurs.

A very high value of K indicates that at equilibrium most of the reactants are converted into products.

The equilibrium constant K is the ratio of the concentrations of products to the concentrations of reactants raised to appropriate stoichiometric coefficients.

When the value of the equilibrium constant is very high, the concentration of products is much higher than the concentration of reactants.

This means that most of the reactants are converted into products and the position of equilibrium lies far to the right, with products being favoured.

Hence, option A is correct.

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8 0
2 years ago
Why are some substances not able to dissolve in water?
Gemiola [76]
<span>Water is a polar molecule. If a solute dissolved in water is polar molecule, it will dissolve in water. If a solute dissolved in water is non-polar like oil it will not dissolve in water. Polar dissolves in polar.</span>
5 0
3 years ago
Calculate the solubility of zn(oh)2(s) in 2.0 m naoh solution. (hint: you must take into account the formation of zn(oh)2−4, whi
Brilliant_brown [7]
When we have:

Zn(OH)2 → Zn2+ 2OH-  with Ksp = 3 x 10 ^-16

and:

Zn2+ + 4OH- → Zn(OH)4 2-  with Kf = 2 x 10^15
 
by mixing those equations together:

Zn(OH)2 + 2OH- → Zn(OH)4 2- with K = Kf *Ksp = 3 x 10^-16 * 2x10^15 =0.6

by using ICE table:

         Zn(OH)2 + 2OH- → Zn(OH)4 2-

initial                     2m              0

change                  -2X                +X     

Equ                       2-2X                 X

when we assume that the solubility is X

and when K = [Zn(OH)4 2-] / [OH-]^2

        0.6 = X / (2-2X)^2    by solving this equation for X

∴ X = 0.53 m

∴ the solubility of Zn(OH)2 = 0.53 M
4 0
3 years ago
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