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Snezhnost [94]
3 years ago
15

Fossil fuels are:

Chemistry
1 answer:
Scorpion4ik [409]3 years ago
7 0

Answer:

d

Explanation:

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How many moles of S are in 35.4 g of (C3H5)2S?
alexandr402 [8]
<span>0.310 moles First, look up the atomic weights of the elements involved. Atomic weight carbon = 12.0107 Atomic weight hydrogen = 1.00794 Atomic weight sulfur = 32.065 Molar mass (C3H5)2S = 6 * 12.0107 + 10 * 1.00794 + 32.065 = 114.2086 g/mol Moles (C3H5)2S = 35.4 g / 114.2086 g/mol = 0.309959145 mol Since there's just one sulfur atom per (C3H5)2S molecule, the number of moles of sulfur will match the number of moles of (C3H5)2S which is 0.310 when rounded to 3 significant digits.</span>
6 0
3 years ago
What is the balanced equation for the manufacture of ethanol from glucose
Darina [25.2K]

Answer:

C6H12O6 → 2C2H5OH + 2CO2

Explanation:

Glucose is an organic molecule, specifically a sugar, with the formula C612O6 while ethanol is another organic molecule with formula; C2H5OH.

However, as rightly said in this question, ethanol can be got from glucose via a process called fermentation in the presence of a catalyst called YEAST. The balanced equation is as follows:

C6H12O6 → 2C2H5OH + 2CO2

7 0
3 years ago
How many molecules are there in 7.27 miles of ammonia?
NemiM [27]

Hey There!

To solve this question remember that 1 mole of ammonia is equal to 17G of ammonia.

Using that, we first multiply 17 by 7 = 24

Then we multiply 7 by .27 = 1.89

Finally, taking those and adding them together gives you the answer...

<u>25.89 grams :)</u>

<u></u>

<u>Have a great day, I hope I helped.</u>

<u></u>

<u>+ Brainliest & Five stars are always appreciated </u>

4 0
3 years ago
Read 2 more answers
The majority of the world’s water is stored in?
aniked [119]

Answer:

Ocean

Explanation:

97 percent of the water in the world is in the ocean.

The 3 percent of freshwater is located in lakes, streams, glaciers, and can be found underground.

8 0
3 years ago
How much of 0.5 M HNO3 is necessary to titrate 25.0 mL of 0.05 M KOH
Ivan

Answer: 2.5 ml of 0.5 M HNO3 is necessary to titrate 25.0 mL of 0.05 M KOH

solution to the endpoint

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HNO_3

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH.

We are given:

n_1=1\\M_1=0.5M\\V_1=?mL\\n_2=1\\M_2=0.05M\\V_2=25.0mL

Putting values in above equation, we get:

1\times 0.5\times V_1=1\times 0.05\times 25.0\\\\V_1=2.5mL

Thus 2.5 ml of 0.5 M HNO3 is necessary to titrate 25.0 mL of 0.05 M KOH

solution to the endpoint

6 0
3 years ago
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