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Anna11 [10]
3 years ago
6

Richard and samantha are charting their monthly cash flow. They have some expenses like car repairs and vacations that are not p

aid each month. How can they account for these non-monthly expenses ?
Mathematics
1 answer:
sdas [7]3 years ago
6 0
They can put them into a chart called unexpected expenses. 

This way they can take vacations or if they have car troubles 


It would make their life so much easier
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I need the equation for this ASAP!
Sindrei [870]

Answer:

5.714 liters of the 5% solution and 4.286 of the 40%.

Step-by-step explanation:

Let x be the volume of 40% solution and y = volume of the 5% solution.

x + y = 10

0.40x + 0.05y = 0.20(x + y)

From the first equation x = 10 -y so we have:

0.40(10 - y) + 0.05y = 0.20( 10 - y + y)

4 - 0.40y + 0.05y = 2

-0.35y = -2

y = 5.714 liters of the 5%.

and x =  10 - 5.714 = 4.286  liters of the 40% solution.

Step-by-step explanation:

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3 years ago
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What math do high schoolers learn? Do they only learn trigonometry, geometry and equations?
EleoNora [17]

Answer:

trigonometry

Step-by-step explanation:

hopes this helps

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2 years ago
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X-y=1,y=5<br> What is the answer to this problem ?
Karo-lina-s [1.5K]

Answer: x = 6 y = 5

Step-by-step explanation: coz I juss know

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3 years ago
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If p(a | b) = 0.4, p(b) = 0.8, and p(a) = 0.5, are the events a and b independent?
pashok25 [27]

The events A and B are not independent.

Given that,

                  P(A|B) = 0.4

                  P(A) = 0.5

                  P(B) = 0.8

Two events A and B are said to be independent, if P(A∩B) = P(A) P(B)

We have, P(A|B) = P(A∩B)/P(B)

Therefore, P(A∩B) = P(A|B) P(B) = 0.4 x 0.8 = 0.32

Now P(A) P(B) = 0.5 x 0.8 = 0.4

So P(A∩B) ≠ P(A)P(B)

Therefore, the events A and B are not independent.

Learn more about independent events at brainly.com/question/22881926

#SPJ4

7 0
2 years ago
Jane, Jasmine, and Jocelyn have record collections. Jane has 3 times as many records as Jocelyn has. Jasmine has 2 more than twi
dangina [55]
X = jane, y = jasmine, z = jocelyn

x + y + z = 56
x = 3z
y = 2z + 2

3z + 2z + 2 + z = 56
6z + 2 = 56
6z = 56 - 2
6z = 54
z = 54/6
z = 9 <==== jocelyn

x = 3z
x = 3(9)
x = 27 <=== jane

y = 2z + 2
y = 2(9) + 2
y = 18 + 2
y = 20 <=== jasmine
7 0
3 years ago
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