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Anna11 [10]
3 years ago
6

Richard and samantha are charting their monthly cash flow. They have some expenses like car repairs and vacations that are not p

aid each month. How can they account for these non-monthly expenses ?
Mathematics
1 answer:
sdas [7]3 years ago
6 0
They can put them into a chart called unexpected expenses. 

This way they can take vacations or if they have car troubles 


It would make their life so much easier
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Find the area of a trapezium whose parallel sides are 28.7 cm and 22.3 cm and distance between parallel sides is 16 cm.
puteri [66]

Given:

The parallel sides of a trapezium are 28.7 cm and 22.3 cm.

The distance between parallel sides is 16 cm.

To find:

The area of a trapezium.

Solution:

The area of the trapezium is:

A=\dfrac{a+b}{2}h

Where, a,b are parallel sides and h is the vertical distance between the parallel sides.

Putting a=28.7, b=22.3,h=16 in the above formula, we get

A=\dfrac{28.7+22.3}{2}\times(16)

A=\dfrac{51}{2}\times 16

A=51\times 8

A=408

Therefore, the area of the trapezium is 408 square cm.

4 0
3 years ago
Shona drove 264 miles in 5.5 hours at this rate how far can she drive in 7 hours
Marianna [84]
5.5hours to drive264 miles
7 hours to drove (264÷5.5)× 7 =....
5 0
2 years ago
The population of a city in 2000 was 500,000 while the population of the suburbs of that city in 2000 was 700,000. Suppose that
Mnenie [13.5K]

Answer:

The population of the city in 2002 is 469,280 while the population of the suburb is 730,720.

Step-by-step explanation:

  • 6% of the city's population moves to the suburbs (and 94% stays in the city).
  • 2% of the suburban population moves to the city (and 98% remains in the suburbs).

The migration matrix is given as:

A= \left \begin{array}{cc}  \\ C \\S \end{array} \right\left[ \begin{array}{cc}  C&S\\ 0.94&0.06 \\0.02&0.98 \end{array} \right]

The population in the  year 2000 (initial state) is given as:

\left[ \begin{array}{cc}  C&S\\ 500,000&700,000  \end{array} \right]

Therefore, the population of the city and the suburb in 2002 (two years after) is:

S_0A^2=\left \begin{array}{cc} [500,000&700,000]\\&  \end{array} \right\left \begin{array}{cc} \end{array} \right\left[ \begin{array}{cc} 0.94&0.06 \\0.02&0.98 \end{array} \right]^2

A^{2} = \left[ \begin{array}{cc} 0.8848 & 0.1152 \\\\ 0.0384 & 0.9616 \end{array} \right]

Therefore:

S_0A^2=\left \begin{array}{cc} [500,000&700,000]\\&  \end{array} \right\left \begin{array}{cc} \end{array} \right \left[ \begin{array}{cc} 0.8848 & 0.1152 \\ 0.0384 & 0.9616 \end{array} \right]\\\\=\left[ \begin{array}{cc} 500,000*0.8848+700,000*0.0384& 500,000*0.1152 +700,000*0.9616 \end{array} \right]\\\\=\left[ \begin{array}{cc} 469280& 730720 \end{array} \right]

Therefore, the population of the city in 2002 is 469,280 while the population of the suburb is 730,720.

6 0
3 years ago
Help !.!.!.!.!.!.!!.!.!.!.!.!.!.!.!.!.!.!.!.!.
Elena-2011 [213]

Answer:

1.5 km

Step-by-step explanation:

15 cm * 10 000 = 150 000 cm = 1.5 km

6 0
2 years ago
Read 2 more answers
Need answers pls I am struggling!
Lady bird [3.3K]

Answer:

(1)....27

(2)...30

ans...............

6 0
2 years ago
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