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Answer:
from O toWl Q partical is accelerating with constant magnitude. and from Q to P is decelerating with constant magnitude.
Explanation:
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force= mass × acceleration
Answer;
V = 14.7 m/s
Explanation and solution;
Vx = V cos theta
Vx = 16m/s × cos 28.08
Vx = 14.1 m/s
Vy = Vsin theta
Vy = 7.51m/s
t = d/Vx
t = 16.8m/ 14.1
t= 1.191 s
Now, find Vy at t= 1.191
Vy = Vy - gt
Vy = 7.51 - 9.81*1.191
Vy = - 4.18 m/s
V = sqrt (Vy^2 +Vx^2)
V= sqrt (4.18^2 + 14.1^2)
V= 14.7m/s
Answer:
The angle between the red and blue light inside the glass is 1.9°.
Explanation:
Given that,
Refractive index
For blue = 1.64
For red = 1.54
Incident angle = 48°
We need to calculate the angle between the red and blue light inside the glass
Using Snell's law
![\dfrac{\sin_{i}}{\sin_{r}}=n](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csin_%7Bi%7D%7D%7B%5Csin_%7Br%7D%7D%3Dn)
For blue ray,
![\dfrac{\sin_{i}}{\sin_{r_{b}}}=n_{b}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csin_%7Bi%7D%7D%7B%5Csin_%7Br_%7Bb%7D%7D%7D%3Dn_%7Bb%7D)
![r_{b}=\sin^{-1}\dfrac{\sin48^{\circ}}{n_{b}}](https://tex.z-dn.net/?f=r_%7Bb%7D%3D%5Csin%5E%7B-1%7D%5Cdfrac%7B%5Csin48%5E%7B%5Ccirc%7D%7D%7Bn_%7Bb%7D%7D)
![r_{b}=\sin^{-1}\dfrac{\sin48^{\circ}}{1.64}](https://tex.z-dn.net/?f=r_%7Bb%7D%3D%5Csin%5E%7B-1%7D%5Cdfrac%7B%5Csin48%5E%7B%5Ccirc%7D%7D%7B1.64%7D)
![r_{b}=26.95^{\circ}](https://tex.z-dn.net/?f=r_%7Bb%7D%3D26.95%5E%7B%5Ccirc%7D)
For red ray,
![\dfrac{\sin_{i}}{\sin_{r_{r}}}=n_{r}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csin_%7Bi%7D%7D%7B%5Csin_%7Br_%7Br%7D%7D%7D%3Dn_%7Br%7D)
![r_{r}=\sin^{-1}\dfrac{\sin48^{\circ}}{n_{r}}](https://tex.z-dn.net/?f=r_%7Br%7D%3D%5Csin%5E%7B-1%7D%5Cdfrac%7B%5Csin48%5E%7B%5Ccirc%7D%7D%7Bn_%7Br%7D%7D)
![r_{r}=\sin^{-1}\dfrac{\sin48^{\circ}}{1.54}](https://tex.z-dn.net/?f=r_%7Br%7D%3D%5Csin%5E%7B-1%7D%5Cdfrac%7B%5Csin48%5E%7B%5Ccirc%7D%7D%7B1.54%7D)
![r_{r}=28.85^{\circ}](https://tex.z-dn.net/?f=r_%7Br%7D%3D28.85%5E%7B%5Ccirc%7D)
We need to calculate the angle between the red and blue
![r_{rb}=r_{r}-r_{b}](https://tex.z-dn.net/?f=r_%7Brb%7D%3Dr_%7Br%7D-r_%7Bb%7D)
Put the value into the formula
![r_{rb}=28.85-26.95](https://tex.z-dn.net/?f=r_%7Brb%7D%3D28.85-26.95)
![r_{rb}=1.9^{\circ}](https://tex.z-dn.net/?f=r_%7Brb%7D%3D1.9%5E%7B%5Ccirc%7D)
Hence, The angle between the red and blue light inside the glass is 1.9°.