What will happen to the volume if the number of moles of a gas is decreased at constant temperature and pressure?
2 answers:
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<span>Chemical reactions involving only liquids will be influenced by ALL of the following EXCEPT: </span><span><span>c) size of reactant particles d) pressure of the system.
</span>Reason:
1) As per Arrhenius theory, rate of chemical reactions is influence by temperature. Mathematically it is expressed as: k = A exp(-Ea/RT)
</span>where, k = rate constant, A = collision frequency, Ea = activation energy, T = temp. From above relation, it can be seen that, chemical reactions involving only liquids will be influenced temperature.
2) Also, if know that, rates of chemical reactions is mathematically expressed as:![Rate = [A]^{x} B^{y}....](https://tex.z-dn.net/?f=%20Rate%20%3D%20%5BA%5D%5E%7Bx%7D%20B%5E%7By%7D....%20%20)
,
where A, B, .. are the reactants.
From above relation, it can be seen that, chemical reactions involving only liquids will be influenced concentration i.e. number of particle.
3) However, since all the reactant and catalyst used (if any) is in liquid state, particle size of same will not influence the reaction.
4) Also, since there are no gas-phase reactant, pressure will not affect the reaction.
</span>Reason:
1) As per Arrhenius theory, rate of chemical reactions is influence by temperature. Mathematically it is expressed as: k = A exp(-Ea/RT)
</span>where, k = rate constant, A = collision frequency, Ea = activation energy, T = temp. From above relation, it can be seen that, chemical reactions involving only liquids will be influenced temperature.
2) Also, if know that, rates of chemical reactions is mathematically expressed as:
where A, B, .. are the reactants.
From above relation, it can be seen that, chemical reactions involving only liquids will be influenced concentration i.e. number of particle.
3) However, since all the reactant and catalyst used (if any) is in liquid state, particle size of same will not influence the reaction.
4) Also, since there are no gas-phase reactant, pressure will not affect the reaction.
Answer : The molarity of in the solution is 1.5 M.
Explanation : Given,
Moles of = 3.0 mol
Volume of solution = 2.00 L
Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.
Formula used :
Now put all the given values in this formula, we get:
Therefore, the molarity of in the solution is 1.5 M.