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Inessa05 [86]
3 years ago
15

Read the excerpt from Neil deGrasse Tyson’s “Death by Black Hole.” Black holes are regions of space where the gravity is so high

that the fabric of space and time has curved back on itself, taking the exit doors with it. Another way to look at the dilemma: the speed required to escape a black hole is > the speed of light itself. . . . light travels at exactly 299,792,458 meters per second in a vacuum and is the fastest stuff in the universe. If light cannot escape, then neither can you, which is why, of course, we call these things black holes. Which of the following features would best enhance the reader’s understanding of this excerpt?
a photograph of a black hole
a demonstration of the speed of light
an interactive animation of a black hole
a definition of the term black hole
Physics
2 answers:
kakasveta [241]3 years ago
8 0

Answer: a definition of the term black hole

kramer3 years ago
4 0
<h2>Answer: a definition of the term black hole</h2>

This text is clearly a definition of the term black hole, made by the American astrophysicist Neil deGrasse Tyson.

However, the discussions about this subject are not new, since Einstein's theory of relativity already defined what a black hole is.

In this sense, a black hole is described as a "singularity" that consists of <u>a region of the space in which the density of matter tends to infinity.</u>

Although this is hard to find possible for classical physics; following what relativity establishes:<em> bodies within a gravitational field follow a curved space path. Then the more a body enters the black hole, the more curved the space will become, until, in the center, it will become infinitely curved. </em>

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4 years ago
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A child and sled with a combined mass of 58.0 kg slide down a frictionless slope. If the sled starts from rest and has a speed o
erma4kov [3.2K]

Answer:

The height is  h = 0.5224 \ m

Explanation:

From the question we are told that

   The combined mass of the child and the sled is  m =  58.0 \  kg

    The  speed of the sled is  u = 3.20 \ m/s

Generally applying SOHCAHTOA on the slope which the combined mass is down from

   Here the length of the slope(L)  where the combined mass slides through  is the hypotenuses

   while the height(h) of the height of the slope is the opposite

Hence from SOHCAHTOA

      sin (\theta) =  \frac{h}{L}

=>   Lsin(\theta) = h

Generally from the kinematic equation we have that

   v^2  = u^2 + 2aL

Here the u  is the initial velocity of the combined mass which is zero since it started from rest

 and  a is the acceleration of the combined mass which is mathematically evaluated as

       a =  g * sin (\theta )

      v^2  = u^2 + 2 *  g * sin (\theta )L

=>   2Lsin(\theta ) =  \frac{v^2 - u^2 }{g}

=>   h = \frac{ v^2 - u^2}{2g}

=>   h = \frac{ 3.20^2 - 0^2}{2 * 9.8 }

=>   h = 0.5224 \ m

6 0
3 years ago
I am best known for publishing an almanac based on my astronomical calculations. Who am i?
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A cylinder contains 3.0 L of oxygen at 310 K and 2.5 atm. The gas is heated, causing a piston in the cylinder to move outward. T
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Answer:

The gas pressure is: 1.55 atm.

Explanation:

We need to use the equation that relate the variables given at the exercise (pressure, temperature and volume) from the ideal gas law formula, when the mass is constant we can reduce the expretion PV=nRT to \frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2} } solving to P2 we get:\frac{P_{1}V_{1}T_{2}}{T_{1}V_{2}}=P_{2} replace the values P_{2}=\frac{2.5*3*610}{9.5*310} =1.55(atm).

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