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nalin [4]
3 years ago
10

Help please!!

Physics
1 answer:
AleksAgata [21]3 years ago
8 0
Speed is rate of an object moving all together, it has a scalar quantity.

Velocity is <span>which a object is moving in a specific direction, it has </span>a vector quantity.


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2. Why are the health-related fitness components more
ser-zykov [4K]

Answer:

Health-related physical fitness is primarily associated with disease prevention and functional health.

Explanation:

This is ur answer actually I just took it from Go ogle

7 0
3 years ago
For each question, select the right answer from the choices below:
Leni [432]

Option (ii) B is the correct option. The object on the moon has greater mass.

To resolve this, utilize the formulas Force = Mass * Acceleration.

The equation can be used to find the mass given the force in Newtons, using 9.8 m/s² for the acceleration of gravity of the earth and 1.6 m/s² for the moon.

Calculating the mass on earth:

30 N = 9.8 m/s² * mass

This results in a mass of 3.0 kg for the object on Earth.

Calculating the mass of the moon:

30 N = 1.6 m/s²2 * mass

Thus, the moon's object has a mass of 19. kg.

This can be explained by the fact that the earth has a stronger gravitational pull than the moon, producing more force per kilogram of mass. As a result, the moon's mass must be bigger to produce the same amount of force at a lower acceleration from gravity (1.6 m/s² vs. 9.8 m/s²).

To know more about Mass, refer to this link :

brainly.com/question/13386792

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3 0
1 year ago
..................................
sammy [17]

Hi, what is it you need help with?

8 0
2 years ago
A 70.0-kg skier is sliding at 4 m/s when they slide down a 2m high hill. At the bottom of the hill they run into a large 2800 N/
Katarina [22]

Answer:

\Delta x=245\ mm

Explanation:

Given:

  • mass of skier, m=70\ kg
  • initial velocity of skier, u=4\ m.s^{-1}
  • height of the hill, h=2\ m
  • spring constant, k=2800\ N.m^{-1}

<u>final velocity of skier before coming in contact of spring:</u>

Using eq. of motion:

v^2=u^2+gh

v^2=4^2+9.8\times 2

v=5.9666\ m.s^{-1}

<u>Now the time taken by the skier to reach down:</u>

v=u+gt

5.9666=4+9.8\ t

t=0.2007\ s

<u>Now we calculate force using Newton's second law:</u>

F=\frac{dp}{dt}

F=\frac{m(v-u)}{t}

F=\frac{70\times(5.9666-4)}{0.2007}

F\approx686\ N

<u>∴Compression in spring before the skier momentarily comes to rest:</u>

\Delta x=\frac{F}{k}

\Delta x=\frac{686}{2800}

\Delta x=0.245\ m

\Delta x=245\ mm

4 0
3 years ago
An object accelerates at 32 m/s² when a force of 71 N is applied to it. What is the object’s mass? show your work
amid [387]

Answer:

Its  answer is 2.21 kg.

Explanation:

F =m × a

71 = m × 32

71 ÷ 32 = m

2.21 kg = m

6 0
3 years ago
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