Answer: option C. Copper (II) chloride
Explanation:
To name CuCl2, we need to know the oxidation state of Cu in the compound as chlorine always have oxidation on —1 in all its compound. The oxidation state of Cu can be calculated as follows:
Cu + 2Cl = 0 (since the compound has no charge)
Cl = —1
Cu + 2(—1) = 0
Cu —2 = 0
Collect like terms
Cu = 0 +2
Cu = +2
Therefore, the oxidation state of Cu in CuCl2 is +2.
The name of the compound will be copper(ii) chloride, since cupper has oxidation state +2 in the compound.
Answer:
Hydrogen sulfide
Explanation:
A nonoxidizing acid is the acid which cannot act as oxidizing agent and thus furnish hydrogen ions. Example: HCl
Iron(II) sulfide reacts with nonoxidizing acid, say hydrochloric acid to give rotten egg smelling gas, H₂S (Hydrogen sulfide).
The reaction is shown below:
FeS (s) + 2HCl (aq) ⇒ FeCl₂ (s) + H₂S (g)
A general reaction is also shown below of the reaction of Iron(II) sulfide with any nonoxidizing acid, HX as:
FeS (s) + 2HX (aq) ⇒ FeX₂ (s) + H₂S (g)
