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mamaluj [8]
3 years ago
6

Some compounds, like carbon dioxide, are gaseous at room temperature, while others are solid at room temperature. Why is this?

Chemistry
1 answer:
OverLord2011 [107]3 years ago
3 0

Compounds that are gases at room temperature are covalent bonds (nonmetal + nonmetal).

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URGENT!! Chemistry gurus-- I summon thee!
Elina [12.6K]

1. Molarity : 0.25 M

2. mol CH₄ = 7.4 moles

mol O₂ = 14.8 moles

<h3>Further explanation</h3>

1.

Given

83.2 g CuCl2 in 2.5 liters of water

Required

the molarity

Solution

Molarity : mol solute per liter of solution(not per liter of solvent)

  • mol solute

mol solute = mol CuCl₂

mol CuCl₂ = mass : MW CuCl₂

mol CuCl₂ = 83.2 : 134.45

mol CuCl₂ = 0.619

  • Molarity

Molarity(M) = mol : V

Assume density CuCl₂ = 3.39 g/cm³

volume CuCl₂ = 8.32 g : 3.39 g/cm³ = 2.45 cm³=2.45 x 10⁻³ L

With this small volume value of CuCl₂, the volume of the solute is sometimes neglected in calculating molarity

volume of solution = 2.5 L + 2.45 x 10⁻³ L = 2.50245 L

Molarity(M) = mol : V

M = 0.619 : 2.50245 L = 0.247≈0.25

2.

Given

Reaction

The correct balanced reaction:

CH4 + 2O2 → CO2 + 2H2O

7.4 moles CO2

Required

moles of methane (CH4) and oxygen gas (O2)

Solution

From the equation, mol ratio of CO₂ : CH₄ : O₂ = 1 : 1 : 2

mol CH₄ = mol CO₂ = 7.4 moles

mol O₂ = 2 x mol CO₂ = 2 x 7.4 moles = 14.8 moles

3 0
3 years ago
How many atoms are present in 3 moles of chromium?
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Answer:

1.80 x 10^24 atoms

Explanation:

3moles × 6.022×10^23 atoms/mole

3 0
3 years ago
If the half-life of 37Rb is 4.7x101 years, how long would it take for 0.5 grams of a 2 gram sample to radioactively decay?
k0ka [10]

<u>Answer:</u> The time required will be 19.18 years

<u>Explanation:</u>

All the radioactive reactions follows first order kinetics.

The equation used to calculate half life for first order kinetics:

k=\frac{0.693}{t_{1/2}}

We are given:

t_{1/2}=4.7\times 10^1yrs

Putting values in above equation, we get:

k=\frac{0.693}{4.7\times 10^1yr}=0.015yr^{-1}

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}

where,  

k = rate constant  = 0.015yr^{-1}

t = time taken for decay process = ?

[A_o] = initial amount of the reactant = 2 g

[A] = amount left after decay process =  (2 - 0.5) = 1.5 g

Putting values in above equation, we get:

0.015yr^{-1}=\frac{2.303}{t}\log\frac{2}{1.5}\\\\t=19.18yrs

Hence, the time required will be 19.18 years

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3 years ago
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Radda [10]
I think it is an oxygen atom, I am not completely sure though.
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4 years ago
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