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3 years ago

Describe a proton, neutron, and electron. Where are these particles located inside an atom.

2 answers:

4 0

A proton is a positively charged particle found within the nucleus of an atom, a neutron carries no charge and is also found in the nucleus. An electron is a very small negatively charged particle found in the outer "shells" or orbitals of the atom.

lukranit [14]3 years ago

4 0

A proton has a positive charge, a neutron is neutral, and an electron has a negative charge. Protons and electrons are located inside an atom.

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You have a solution of 600 mg of caffeine dissolved in 100 mL of water. The partition coefficient for aqueous caffeine extracted

klio [65]

Answer:

159 mg caffeine is being extracted in 60 mL dichloromethane

Explanation:

Given that:

mass of caffeine in 100 mL of water = 600 mg

Volume of the water = 100 mL

Partition co-efficient (K) = 4.6

mass of caffeine extracted = ??? (unknown)

The portion of the DCM = 60 mL

Partial co-efficient (K) = $\frac{C_1}{C_2}$

where; $C_1=$ solubility of compound in the organic solvent and $C_2$ = solubility in aqueous water.

So; we can represent our data as:

$K=(\frac{A_{(g)}}{60mL} )$ ÷ $(\frac{B_{(mg)}}{100mL} )$

Since one part of the portion is A and the other part is B

A+B = 60 mL

A+B = 0.60

A= 0.60 - B

4.6= $(\frac{0.6-B(mg)}{60mL} )$ ÷ $(\frac{B_{(mg)}}{100mL})$

4.6 = $\frac{(\frac{0.6-B(mg)}{60mL} )}{(\frac{B_{(mg)}}{100mL})}$

4.6 × $(\frac{B_{(mg)}}{100mL})$ = $(\frac{0.6-B(mg)}{60mL} )$

4.6 B $*\frac{60}{100}$ = 0.6 - B

2.76 B = 0.6 - B

2.76 + B = 0.6

3.76 B = 0.6

B = $\frac{0.6}{3.76}$

B = 0.159 g

B = 159 mg

∴ 159 mg caffeine is being extracted from the 100 mL of water containing 600 mg of caffeine with one portion of in 60 mL dichloromethane.

4 0

3 years ago

Read 2 more answers

What is the product of the reaction between HCIO3 and KOH

NISA [10]

Answer:

The products are: KCl03 and H20.

Explanation:

The reaction between HC03 (chloric acid) and KOH (potassium hydroxide) is:

HC03 + KOH ----> KCl03 (KCl03 and H20) + H20 (water)

The reaction is of the double displacement type (in this case parts of the reagents are exchanged, producing two generating new compounds).

7 0

3 years ago

4. Cuál es la aplicación de las reacciones de óxido-reducción en la vida diaria y en la industria?

12345 [234]

Answer:

Dentro de las aplicaciones de la óxido-reducción se pueden encontrar:

La obtención del aluminio a partir de la alúmina y la electrolisis.
La obtención de cloro, hidrógeno e hidróxido de sodio a partir del cloruro de sodio y la electrolisis.
La combustión interna de un motor a gasolina u otro combustible fósil.
Las termoeléctricas, las cuales para generar energía realizan combustión de carbón.
La galvanoplastia, donde para evitar la corrosión de un metal se recubre con otro metal más resistente, por ejemplo: el recubrimiento del acero con zinc.
La pilas o baterías de las cuales se obtiene energía química.

Explanation:

Como puedes ver en la respuesta, la óxido-reducción tiene diversas aplicaciones en la vida moderna, desde todos los tipos de combustión los cuales sirven para brindar energía o movilizarte, hasta todas las funciones que se le ha dado a la electrolisis y a la obtención de la energía por medios químicos, incluso se puede considerar una aplicación de la óxido-reducción la incorporación de antioxidantes en los alimentos, los cuales disminuyen la velocidad de descomposición de los mismos.

3 0

3 years ago

Please Help Weak Acid Base Problems!!!

DiKsa [7]

Answer:

The procedure for calculating the pH of a solution of a weak base is similar to that of the weak acid in the sample problem. However, the variable x will represent the concentration of the hydroxide ion. The pH is found by taking the negative logarithm to get the pOH, followed by subtracting from 14 to get the pH.

Explanation:

3 0

3 years ago

Read 2 more answers

Is oxygen an element?

laiz [17]

Yes oxygen is an element it is
the 8th element
the second period
16th group
noble gas configuration [He]2s^22p^4

7 0

3 years ago