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tensa zangetsu [6.8K]
3 years ago
10

The BMW has an 85L tank while the Cadillac has a 25 gallon tank. Which one has the larger tank?

Physics
2 answers:
PtichkaEL [24]3 years ago
8 0

85 Liters would be around 19 to 20 gallons so it's most likely the Cadillac

Oksi-84 [34.3K]3 years ago
4 0

Answer: 25 gallons on the Cadillac has a little more than than 25 gallons

                                  25gal = 94.635 lit

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frutty [35]

Answer:

(a) You can tell that have the same strength because they have attracted the same amount of paper clips.

(b) Iron is used in electromagnets because steel retained magnetic properties after the power was turned off, but in the iron, the paper clips dropped off right away.

6 0
3 years ago
Heat gained minus work fine is equal to what?
Zina [86]

Heat transferred - Work done = Internal Energy

Explanation:

  • If there is more heat transfer than the work done, the energy difference is called internal energy
  • The first law of thermodynamics equation is given as ΔU=Q−W where, ΔU = Internal energy; Q = Heat transfer; W = Work done
  • Heat = transfer of thermal energy between two bodies at different temperatures
  • Work = force used to transfer energy between a system and its surroundings
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8 0
3 years ago
The space shuttle travels at a speed of about 7.6times10^3 m/s. The blink of an astronaut's eye lasts about 110 ms. How many foo
sveta [45]

Answer:

It covers distance of 9.15 football fields in the said time.

Explanation:

We know that

Distance=Speed\times Time

Thus distance covered in blinking of eye =

Distance=7.6\times 10^{3}m/s\times 110\times 10^{-3}s\\\\Distance=836 meters

Thus no of football fields=\frac{936}{91.4}=9.15Fields

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3 years ago
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lesya692 [45]
The answer is c or h
4 0
4 years ago
The first ionization energy of a hydrogen atom is 2.18 aj (attojoules). what is the frequency and wavelength, in nanometers, of
jasenka [17]

1) Frequency: 3.29\cdot 10^{15}Hz

the energy of the photon absorbed must be equal to the ionization enegy of the atom, which is

E=2.18 aJ=2.18\cdot 10^{-18} J

The energy of a photon is given by

E=hf

where h=6.63\cdot 10^{-34}Js is the Planck's constant. By using the energy written above and by re-arranging thsi formula, we can calculate the frequency of the photon:

f=\frac{E}{h}=\frac{2.18\cdot 10^{-18} J}{6.63\cdot 10^{-34} Js}=3.29\cdot 10^{15} Hz


2) Wavelength: 91.2 nm

The wavelength of the photon can be found from its frequency, by using the following relationship:

\lambda=\frac{c}{f}

where c=3\cdot 10^8 m/s is the speed of light and f is the frequency. Substituting the frequency, we find

\lambda=\frac{3\cdot 10^8 m/s}{3.29\cdot 10^{15}Hz}=9.12\cdot 10^{-8} m=91.2 nm

5 0
3 years ago
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