Answer:
The maximum amount of work is 
Explanation:
From the question we are told that
The temperature of the environment is 
The volume of container A is 
Initially the number of moles is 
The volume of container B is 
At equilibrium of the gas the maximum work that can be done on the turbine is mathematically represented as
![W = P_A V_A ln[ \frac{V_B}{V_A} ]](https://tex.z-dn.net/?f=W%20%3D%20%20P_A%20V_A%20%20ln%5B%20%5Cfrac%7BV_B%7D%7BV_A%7D%20%5D)
Now from the Ideal gas law
So substituting for 
in the equation above
![W = nRT ln [\frac{V_B}{V_A} ]](https://tex.z-dn.net/?f=W%20%3D%20%20nRT%20ln%20%5B%5Cfrac%7BV_B%7D%7BV_A%7D%20%5D)
Where R is the gas constant with a values of 
Substituting values we have that
![W = 1.2 * (8.314) * (280) * ln [\frac{3.5}{2} ]](https://tex.z-dn.net/?f=W%20%3D%201.2%20%2A%20%288.314%29%20%2A%20%28280%29%20%2A%20ln%20%5B%5Cfrac%7B3.5%7D%7B2%7D%20%5D)
Answer:
because of the idea that like charges get repulsion as a force.
Explanation:
because you wrap the ball with foil, the negative charges will leave the foil and go into the ball by induction. This leaves the foil as a positively charged particle since its electrons left it for the ball, making the ball a negatively charged particle. but if you bring the negative charge near the foil, the electrons will transfer from that and go into the foil, making it negatively charged. Now, because the ball and the foil have the same charge, they repel. the foil flies off.
Of the literary devices you provided to choose from, snap hots and thought shots are not even devices so they fall off the list.
sensory language can explain the senses the character is using - helping figure out his reflections,
but figuratve language can helop the best. the character says something figuratively and we can analyze what they meant to find out what they were thinking
Answer:
500cal
Explanation:
Given parameters:
Mass of water = 50g
Initial temperature = 22°C
Final temperature = 32°C
Specific heat of water = 1cal/g
Unknown:
Amount of heat absorbed by the water in calories = ?
Solution:
To solve this problem, we use the expression below:
H = m c Ф
H is the amount of heat absorbed
m is the mass
c is the specific heat capacity
Ф is the temperature change
H = 50 x 1 x (32 - 22) = 500cal
