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Svet_ta [14]
3 years ago
14

the temperature of a gas is increased from 125C to 182C inside of a rigid container. the original pressure of the gas was 1.22at

m, what willl the pressure of the gas be afteer the temperature change
Chemistry
1 answer:
Mariulka [41]3 years ago
5 0

Answer:

1.39 atm

Explanation:

First find combined gas law equation. Then rearrange variable to match problem. You should get...

P2 = P1T2/T1

Next, change celcius temperatures to kelvin. Do this by adding 273 K (standard STP). Then fill in the numbers to go along with equation. You should get...

P2 = 1.22 atm x 455 K / 398 K = 1.39 atm

- If you need further explanation or more help please let me know. I would be glad to offer more of an explanation or help on other problems.

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2 years ago
A speed time graph shows that a car moves at 20 m/s for 15s. The car's speed steadily decreases until it comes to a stop at 40s.
ladessa [460]
0s to 15s: constant speed/zero acceleration
15s to 40s: constant gradient, therefore constant deceleration
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3 years ago
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3 years ago
What do you call A compound composed of two oppositely charged elements?
stepan [7]

Answer: Ionic Bond

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Hope this helped!

5 0
3 years ago
Read 2 more answers
50.0 ml of 0.010m naoh was titrated with 0.50m hcl using a dropper pipet. if the average drop from the pipet has a volume of 0.0
creativ13 [48]

25 drops of acid is required to neutralize the 50.0 ml of 0.010m of NaOH in the experiment.

The equation of the reaction is;

NaOH(aq) + HCl(aq) ---------> NaCl(aq) + H2O(l)

We can use the titration formula;

CAVA/CBVB = NA/NB

CA= concentration of acid

VA = volume of acid

CB = concentration of base

VB = volume of base

NA = number of moles of acid

NB = number of moles of base

CB = 0.010 M

VB = 50.0 ml

CA = 0.50 M

VA = ?

NA = 1

NB = 1

Substituting values;

CAVANB = CBVBNA

VA =  0.010 ×  50.0 × 1/ 0.50 × 1

VA = 1 ml

Since the total volume of acid used is 1 ml and each drop contains 0.040 ml

The number of drops required is 1ml/0.040 ml = 25 drops

Learn more: brainly.com/question/1527403

4 0
3 years ago
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