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Trava [24]
3 years ago
8

What are the benefits and drawbacks of international cooperation in space exploration?

Chemistry
1 answer:
VMariaS [17]3 years ago
3 0
A benefit would be there would be more money for exploration and a con is that there would be a language barrier between the astronauts
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How many atoms are in 10.0 moles of titanium
Tema [17]
The answer should be 479 i could possibly be wrong but that’s what i got because one mole is 47.90 grams
8 0
2 years ago
A concentrated aqueous solution of Pb(NO3)2 is slowly added to 1.0 L of a mixed aqueous solution containing 0.010 M Na2CrO4 and
Oduvanchick [21]

Answer:

This means the amount of PbCrO4 will precipitate first, with a [Pb^2+] concentration of 1.8*10^-12 M

Explanation:

Step 1: Data given

Molarity of Na2CrO4 = 0.010 M

Molarity of NaBr = 2.5 M

Ksp(PbCrO4) = 1.8 * 10^–14

Ksp(PbBr2) = 6.3 * 10^–6

Step 2: The balanced equation

PbCrO4 →Pb^2+ + CrO4^2-

PbBr2  → Pb^2+ + 2Br-

Step 3: Define Ksp

Ksp PbCrO4 = [Pb^2+]*[CrO4^2-]

1.8*10^-14 = [Pb^2+] * 0.010 M

[Pb^2+] = 1.8*10^-14 /0.010

[Pb^2+] = 1.8*10^-12 M

The minimum [Pb^2+] needed to precipitate PbCrO4 is 1.8*10^-12 M

Ksp PbBr2 = [Pb^2+][Br-]²

6.3 * 10^–6 = [Pb^2+] (2.5)²

[Pb^2+] = 1*10^-6 M

The minimum [Pb^2+] needed to precipitate PbBr2 is 1*10^-6 M

This means the amount of PbCrO4 will precipitate first, with a [Pb^2+] concentration of 1.8*10^-12 M

5 0
3 years ago
A chemist has synthesized two new dyes based on the molecular structure of plant-based dyes. The lowest energy absorption line f
Nimfa-mama [501]

Answer:

1. The dye that absorbs at 530 nm.

Explanation:

The dye will absorb light to promote the transition of an electron from the HOMO to the LUMO orbital.

The higher the gap, the higher the energy of transition. The energy can be calculated by E = hc/λ, in which h and c are constants and λ is the wavelength.

The equation shows that the higher the energy, the higher the gap and the lower the wavelength.

Therefore, the dye with absorption at 530 nm has the higher HOMO-LUMO gap.

8 0
3 years ago
Part A Which acid in each of the following pairs has the stronger conjugate base? Match the words in the left column to the appr
vichka [17]

Answer:

HF

H₂S

H₂CO₃

NH₄⁺

Explanation:

<em>Which acid in each of the following pairs has the stronger conjugate base?</em>

According to Bronsted-Lowry acid-base theory, <em>the weaker an acid, the stronger its conjugate acid</em>. Especially for weak acids, pKa gives information about the strength of such acid. <em>The higher the pKa, the weaker the acid.</em>

<em />

  • Of the acids HCl or HF, the one with the stronger conjugate base is HF because it is a weak acid.
  • Of the acids H₂S or HNO₂, the one with the stronger conjugate base is    H₂S  because it is a weaker acid. pKa (H₂S) = 7.04 > pKa (HNO₂) = 3.39
  • Of the acids H₂CO₃ or HClO₄, the one with the stronger conjugate base is H₂CO₃ because it is a weak acid.
  • Of the acids HF or NH₄⁺, the one with the stronger conjugate base is NH₄⁺ because it is a weaker acid. pKa (HF) = 3.17 < pKa (NH₄⁺) = 9.25
6 0
3 years ago
Which letter in the diagram above represents a mountain range in the ocean floor
DIA [1.3K]

THE QUESTION:which letter in the diagram above represents a mountain range in the ocean floor  

A.Letter B  

B.letter D  

C.letter E  

D.letter F

THE ANSWER: Based on my research, none of these are truly correct, as A is actually correct. However, I would highly suggests going with B, as it resembles mountains in shape.

5 0
3 years ago
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