2Ω. Based on the graph the resistance of the bulb is 2Ω.
Based on the graph of the image we can see there are a linear proportionality between the voltage and the current. So, we can modeling this problem calculating the slope of the straight line in the graph as follow:
We can write a formula of the form .
From the Ohm's Law we know that the resistance is directly proportional to the voltage and inversely proportional to the current .
From the graph we can see in the x-axis the values of the voltage and the y-axis the value of the current, with the points (x, y) = (2, 1) and (x₁, y₁) = (4, 2) marked in the graph, we can write:
We need to express the equation in the form :
R = 2Ω
Answer:
9194.4278 seconds
Explanation:
Orbital period is given by :
T² = (4π²r³) /GM
G = Gravitational constant = 6.67 * 10^-11
M = 5.9801 * 10^24 kg
r = (3.110 * 10^6 m + 6378000 m) =3110000 + 6378000 = 9488000 m
T² = (4π² * 9488000^3) / (6.67* 10^-11 * 5.9801*10^24)
T² = 3.37197 * 10^22 / 398872670000000
T² = 84537504.161415
T = sqrt(84537504.161415)
T = 9194.4278 seconds
d = 400 m (8 laps) = 2400 m
t = 14.5 min
v = 0
average t = 14.5 min (60 sec per min) = 870 s/8 laps = 108.75 s per lap
speed = distance /time
400/108.75 sec = 3.67 m/s
Answer: A scalar quantity has magnitude but no particular direction and a vector quantity has magnitude and acts in a particular direction.
Explanation:
In order to solve the problem it is necessary to take into account the concepts related to the moment of inertia, and the center of mass of the object.
Our values are given by:
m = 0.514kg
I = 4.7m (each side)
A) For the case when the axis passes through the midpoints of opposite sidesand lies in the plane of the square. The formula is given by,
B) For the case when the axis passes through the midpoint of one of the sides and is perpendicular to the plane of the square. The formula is given by,
C) For the case when the axis lies in the plane of square f passes through two diagonally opposite particles,