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kolbaska11 [484]
3 years ago
8

A spherical ball is dropped through a liquid, explain why it reaches terminal velocity.

Physics
1 answer:
Alekssandra [29.7K]3 years ago
8 0

Probably because of the drag coefficient and the density of the liquid.

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g A simple pendulum (consisting of a point mass suspended by a massless string) on the surface of the earth has a period of 1.00
leonid [27]

Answer:

Explanation:

The formula for time period of a pendulum is given as follows :

T = 2π\sqrt{\frac{l}{g} }

l is length of pendulum and g is acceleration due to gravity .

So time period of pendulum  is not dependent on the mass of the pendulum . If time period is same and length is also the same then acceleration due to gravity will also be the same . Hence the acceleration due to gravity at distant planet will be same as that on the earth.

5 0
3 years ago
A string attached to an airborne kite was maintained at an angle of 40.0 with the ground. if 120m of string was reeled in to ret
AleksAgata [21]
The hypotenuse is measured at 120 meters of string, and you need to solve for the leg of the triangle that is horizontal. The degree is 40, so use trigonometry to figure it out. 
Cosin (40) is equal to around .766 
Adjacent/Hypotenuse 
x/120 = cos40 
Answer: 91.92533. 
If you use 3 significant figures it should be 91.9 meters.
5 0
3 years ago
an Olympic runner leaps over a hurdle.if the runner initial vertical speed is 2.2m/s how much will the runners center of mass be
Snowcat [4.5K]
Supposing the runner is condensed to a point and moves upward at 2.2 m/s.
It takes a time = 2.2/g = 2.2/9.8 = 0.22 seconds to increase to max height. 
Now looking at this condition in opposite - that is the runner is at max height and drops back to earth in 0.22 s (symmetry of this kind of motion). 
From what height does any object take 0.22 s to fall to earth (supposing there is no air friction)? 
d = 1/2gt²= (0.5)(9.8)(0.22)²= 0.24 m
7 0
3 years ago
A plane leaves Hartsfield Airport and flies around the world returning to Hartsfield airport What is the planes displacement?
rewona [7]
The way around the world
5 0
3 years ago
You are on a 4 m high ladder and throw a ball upwards at 12 m/s. It lands on the ground below the ladder.
Gelneren [198K]

a) 2.75 s

The vertical position of the ball at time t is given by the equation

y= h+ut-\frac{1}{2}gt^2

where

h = 4 m is the initial height of the ball

u = 12 m/s is the initial velocity of the ball (upward)

g = 9.8 m/s^2 is the acceleration of gravity (downward)

We can find the time t at which the ball reaches the ground by substituting y=0 into the equation:

0 = 4 + 12t - 4.9 t^2

This is a second-order equation. By solving it for t, we find:

t = -0.30 s

t = 2.75 s

The first solution is negative, so we discard it; the second solution, t = 2.75 s, is the one we are looking for.

b) -15.0 m/s (downward)

The final velocity of the ball can be calculated by using the equation:

v=u-gt

where

u = 12 m/s is the initial (upward) velocity

g = 9.8 m/s^2 is the acceleration of gravity (downward)

t is the time

By subsisuting t = 2.75 s, we find the velocity of the ball as it reaches the ground:

v=12 -(9.8)(2.75)=-15.0 m/s

And the negative sign means the direction is downward.

7 0
3 years ago
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