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notsponge [240]
1 year ago
12

Grrr i don't have much time, help please T^T

Physics
2 answers:
mart [117]1 year ago
4 0

Answer:

2. ( b ) zero

3. ( c ) 10 s

4. Uniform then decreasing

Explanation:

2.

Since the motion is uniform, initial and final velocity will be 0, hence acceleration will be zero.

3.

Initial velocity ( u ) = 5 m/s

Final velocity ( v ) = 35 m/s

Acceleration ( a ) 3 m/s^2

To find : Time ( t )

Formula : -

t = v - u / a

 = 35 - 5 / 3

 = 30 / 3

t = 10 s

alekssr [168]1 year ago
4 0

Answer:

See below ~

Explanation:

<u>Q2</u>

The uniform circular motion in the movement of object in a circular path with fixed and perpendicular on the direction of the motion acceleration.

  • d

<u>Q3</u>

  • Substitute the values in : <u>v = u + at</u>
  • 35 = 5 + 3t
  • 3t = 30
  • t = 10s (c)

<u>Q4</u>

The vertical component for a projectile by acute angle on the horizontal axis changes from decreasing then increasing velocity.

  • d
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A catapult launches a test rocket vertically upward from a well, giving the rocket an initial speed of 79.6 m/s at ground level.
Dimas [21]

Answer:

The rocket is motion above the ground for 44.7 s.

Explanation:

The equations for the height of the rocket are as follows:

y = y0 + v0 · t + 1/2 · a · t²

and, after the engine fails:

y = y0 + v0 · t + 1/2 · g · t²

Where:

y = height of the rocket at time t

y0 =  initial height

v0 = initial speed

t=  time

a = acceleration due to the engines

g = acceleration due to gravity

First, let´s calculate the time the rocket is being accelerated by the engines:

(The center of the framer of reference is located at the ground, y0 = 0).

y = y0 + v0 · t + 1/2 · a · t²

1190 m = 0 m + 79.6 m/s · t + 1/2 · 4.10 m/s² · t²

0 = 2.05  m/s² · t² + 79.6 m/s · t - 1190 m

Solving the quadratic equation:

t = 11.5 s  (the other value of t is discarded because it is negative).

At that time, the engines fail and the rocket starts to fall. The equation of the height will be:

y = y0 + v0 · t + 1/2 · g · t²

The initial velocity (v0) will be the velocity acquired during 11.5 s of acceleration plus the initial velocity of launch:

v = v0 + a · t

v = 79.6 m/s + 4.10 m/s² · 11.5 s

v = 126.8 m/s

Now, we can calculate the time it takes the rocket to reach the ground (y = 0) from a height of 1190 m:

y = y0 + v0 · t + 1/2 · g · t²

0 m = 1190 m + 126.8 m/s · t - 1/2 · 9.80 m/s² · t²

Solving the quadratic equation:

t = 33.2 s

Then, the total time the rocket is in motion is (33.2 s + 11.5 s) 44.7 s

 

5 0
3 years ago
A parallel plate capacitor can store
Norma-Jean [14]
A parallel plate capacitor can store electric charge and
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3 0
3 years ago
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The acceleration due to gravity on the Moon's surface is
Molodets [167]

Answer:

50 lb

Explanation:

Given,

The weight of astronaut's life support backpack on Earth (w) = 300 lb

Acceleration due to gravity on Earth (g) = 9.8 m/s²

Acceleration due to gravity on Moon = g'

g'=\frac{g}{6}

We know that weight of an object on Earth is,

w = m\times g

m = \frac{w}{g}

Similarly, weight on Moon will be

w' = m\times g'

w' = \frac{w}{g}\times\frac{g}{6}

w' = \frac{300}{6}

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7 0
3 years ago
What is the DISPLACEMENT of the motorbike rider in the picture?
lutik1710 [3]
120m north east hope this helps
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URGENTE ¿Cuál de los siguientes términos corresponde al concepto presión? * A. Es la fuerza perpendicular que ejerce un cuerpo s
melomori [17]

Answer:

Respuesta correcta, opción D: Es la fuerza que un cuerpo ejerce perpendicularmente sobre el área en la que actúa.

Explanation:

La definición de presión es la fuerza que un cuerpo ejerce en dirección perpendicular sobre el área en la que actúa.

Cuando se aplica una fuerza sobre la superficie de un cuerpo, la presión es la siguiente:

P = \frac{F}{A}

En donde:

F es la fuerza aplicada.

A es el área del cuerpo.  

Por lo tanto la opción correcta es la D: es la fuerza que un cuerpo ejerce perpendicularmente sobre el área en la que actúa.

Espero que se sea de utilidad!      

6 0
2 years ago
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