What is the expected oxidation state for the most common ion of element 2

Chemistry

1 answer:

lozanna [386]2 years ago

3 0

Answer: 1+

Justification:

The ionization energies tell the amount of energy needed to release an electron and form a ion. The first ionization energy if to loose one electron and form the ion with oxidation state 1+, the second ionization energy is the energy to loose a second electron and form the ion with oxidation state 2+, the third ionization energy is the energy to loose a third electron and form the ion with oxidation state 3+.

The low first ionization energy of element 2 shows it will lose an electron relatively easily to form the ion with oxidations state 1+.

The relatively high second ionization energy (and third too) shows that it is very difficult for this atom to loose a second electron, so it will not form an ions with oxidation state 2+. Furthermore, given the relatively high second and third ionization energies, you should think that the oxidation states 2+ and 3+ for element 2 never occurs.

Therefore, the expected oxidation state for the most common ion of element 2 is 1+.

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Which process transfers heat from the ground to the air touching it? Conduction Convection Evaporation Radiation

Delicious77 [7]

Convection

Explanation:

Heat is a form of thermal energy borne as result of thermal energy. It is observed as temperature differences between places.

There are different types of heat transfer:

Conduction
Convection
Radiation

Conduction is a heat transfer which involves the actual movement of the collision of the molecules of the medium.

Convection is a heat transfer in fluids by their movement from areas of higher to places of lower heat.

Radiation is heat transfer using electromagnetism and does not involve molecules of the medium

The process of heat transfer from ground to the air touching it is convection. It involves particles of the air.

Learn more:

Convection brainly.com/question/1140127

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8 0

3 years ago

MARKING BRAINLIEST! please help asap, i need a and b, thank you

defon

The time required to reduce the concentration from 0.00757 M to 0.00180 M is equal to 1.52 × 10⁻⁴ s. The half-life period of the reaction is 9.98× 10⁻⁵s.

<h3>What is the rate of reaction?</h3>

The rate of reaction is described as the speed at which reactants are converted into products. A catalyst increases the rate of the reaction without going under any change in the chemical reaction.

Given the initial concentration of the reactant, C₀= 0.00757 M

The concentration of reactant after time t is C₁= 0.00180 M

The rate constant of the reaction, k = 37.9 M⁻¹s⁻¹

For the first-order reaction: $C_t =C_0-kt$