Answer:
“I think it’s about putting yourself in the students’ shoes and seeing how a first-time student, maybe someone who hasn’t even taken chemistry before, is looking at it.”
—Valerie Taraborelli, undergraduate chemistry student, University of Arizona1
“In some ways, I think the people who are the most successful as teachers are the ones who are able to remember what it was like being uncertain and not knowing. When you become an expert, things are easy. So the idea is to try and see where [students] are coming from and why they’ve developed this misconception and what you can do to specifically address it.”
—Dee Silverthorn, biology professor, University of Texas2
<h2>Hope this helps !! </h2>
Education is payed for with tax dollars
Answer:
magnification is 4
Explanation:
m= image height / object height
m= 12/3
m= 4
Answer:
a) Δx₂ = 31*Δt
b) Δx₁ = 977.5 / a
c) a = 23 / Δt
e) Δx₁ = 42.5*Δt
g) Δt = 0.0565 h
i) a = 0.05 m/s²
Explanation:
Given
v₁ = 54 Mi/h
v₂ = 31 Mi/h
a) We apply the formula
Δx₂ = v₂*Δt
⇒ Δx₂ = 31*Δt (Assuming constant speed)
b) We use the formula
v₂² = v₁² - 2*a*Δx₁ ⇒ Δx₁ = (v₁² - v₂²) / (2*a)
⇒ Δx₁ = (54² - 31²) / (2*a)
⇒ Δx₁ = 977.5 / a
c) We use the equation
v₂ = v₁ - a*Δt ⇒ a = (v₁ - v₂) / Δt
⇒ a = (54 - 31) / Δt
⇒ a = 23 / Δt
e) We apply the formula
Δx₁ = v₁*Δt - 0.5*a*Δt²
Δx₁ = 54*Δt - 0.5*(23 / Δt)*Δt²
⇒ Δx₁ = 42.5*Δt
g) If Δx₁ = 2.4 Mi ⇒ 2.4 = 42.5*Δt ⇒ Δt = 0.0565 h
i) If a = 23 / Δt ⇒ a = 23 Mi / 0.0565 h = 407.29 Mi/h²
⇒ a = 0.05 m/s²
