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a_sh-v [17]
2 years ago
13

What is the total momentum of a 30 kg object traveling left at 3 m/s and a 50 kg object traveling at 2 m/s to the right?

Physics
1 answer:
madam [21]2 years ago
4 0

Answer:

there are 25 kg objective travelling at 2m/s to the right.

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PLEASE HELP ME I AM TIMED!
Leno4ka [110]

Answer:

Well my good friend the other person did not give U a good answer, it is actually the third one

Explanation: well it is the most logical of all the answers if you think about it and a lot of the creatures we have in the water today are thought of to have once lived on land based on the fossils we still find to this very day my friend

3 0
3 years ago
By what factor does the peak frequency change if the celsius temperature of an object is doubled from 20.0 ∘c to 40.0 ∘c?
mart [117]

Answer:

it increases by a factor 1.07

Explanation:

The peak wavelength of an object is given by Wien's displacement law:

\lambda=\frac{b}{T} (1)

where

b is the Wien's displacement constant

T is the temperature (in Kelvins) of the object

given the relationship between frequency and wavelength of an electromagnetic wave:

f=\frac{c}{\lambda}

where c is the speed of light, we can rewrite (1) as

\frac{c}{f}=\frac{b}{T}\\f=\frac{Tc}{b}

So the peak frequency is directly proportional to the temperature in Kelvin.

In this problem, the temperature of the object changes from

T_1 = 20.0^{\circ}+273=293 K

to

T_2 = 40.0^{\circ}+273 = 313 K

so the peak frequency changes by a factor

\frac{f_2}{f_1} \propto \frac{T_2}{T_1}=\frac{313 K}{293 K}=1.07

8 0
3 years ago
uring the investigation of a traffic accident, police find skid marks 89.9 m long. They determine the coefficient of friction be
aivan3 [116]

Answer:

V_{0}=29.68m/s

Explanation:

In order to solve this problem, we must first do a drawing of the situation (see attached picture).

When the brakes of the car were applied, we can see that there was only one horizontal force affecting the vehicle's movement, which was the force of friction. When analyzing the free body diagram we can apply Newton's laws to determine the equations we will use to solve this.

\sum F_{x}=ma

so:

-f=ma

we also know that:

f=N\mu_{k}

so

-N\mu_{k}=ma

we can now solve for the acceleration, so we get:

a=\frac{-N\mu_{k}}{m}

we don't know what the normal force is, so we can find it out by analyzing the vertical forces applied to the car:

\sum F_{y}=0

so we get:

N-W=0

which means that:

N=W

we also know that:

W=mg

so

N=mg

we can substitute this into the first equation so we get:

a=\frac{-mg\mu_{k}}{m}

which simplifies to:

a=-g\mu_{k}

we can now substitute the provided data:

a=(-9.8m/s^{2})(0.5)

which yields:

a=-4.9m/s^{2}

once we got the acceleration, we can use kinematics formulas to solve this, we got the following formula:

a=\frac{V_{f}^{2}-V_{0}^{2}}{2x}

we know the final velocity must be zero, since that's where the car got to a stop, so the formula then becomes:

a=-\frac{V_{0}^{2}}{2x}

we can now solve for the initial velocity, which yields:

V_{0}=\sqrt{-2xa}

so we can now substitute the daa we know, so we get:

V_{0}=\sqrt{-2(89.9m)(-4.9m/s^{2})}

so we get:

V_{0}=29.68m/s

So from this we know that the velocity of the car must have been of at least 29.68m/s when the brakes were applied.

4 0
4 years ago
At what height does a 1000-kg mass have potential energy of 1J relative to the ground?
Dvinal [7]

Answer:

0.0001 m

Explanation:

Given

M=1000 KG

PE=1 J

G=9.8 m/s

H=?

Formula

PE = MGH

H= PE/MG

H=1/1000x9.8

H= 1/9800

or 0.00010204

7 0
3 years ago
The short-circuiting logical operators ____. Group of answer choices enable doing as little as is needed to produce the final re
ohaa [14]

Answer:

D. cause the program to stop execution when the expression is evaluated

Explanation:

D. cause the program to stop execution when the expression is evaluated

7 0
4 years ago
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