Answer
given,
largest diameter of balls = 9.52 mm = 0.00476 m
radius = 0.00476
smallest diameter of ball = 2.38 mm = 0.00238 m
radius = 0.00119
viscosity = 1.5 Pa.s
density of the ball = 1.42 g/cm
for small balls
t = 0.033 ms
for larger ball
t = 0.531 ms
Answer:
k = 1400.4 N / m
Explanation:
When the springs are oscillating a simple harmonic motion is created where the angular velocity is
w² = k / m
w =
where angular velocity, frequency and period are related
w = 2π f = 2π / T
we substitute
2π / T = \sqrt{ \frac{k}{m} }
T² = 4π²
k = π²
in this case the period is T = 1.14s, the combined mass of the children is
m = 92.2 kg and the constant of the two springs is
k = 4π² 92.2 / 1.14²
k = 2800.8 N / m
to find the constant of each spring let's use the equilibrium condition
F₁ + F₂ - W = 0
k x + k x = W
indicate that the compression of the two springs is the same, so we could replace these subtraction by another with an equivalent cosecant
(k + k) x = W
2k x = W
k_eq = 2k
k = k_eq / 2
k = 2800.8 / 2
k = 1400.4 N / m
Explanation:
Given that,
Magnitude of electric field in +x direction, E = 4.9 V/m
Part A :
The relation between electric and magnetic field is given by :
c is the speed of light
So, the magnetic field of the wave at this same point in space and instant in time is .\
Part B :
The direction of electric and magnetic field is same i.e. +x direction.
Hence, this is the required solution.
No it cannot because you would have to test it over and over again to make sure it was correct the first time.
Answer:
Explanation:
The electric field on the surface of a conductor is given by:
Here is the surface charge density and the permittivity of free space. Thus, the highest surface charge density that can exist in a conductor is given by the value of the dielectric breakdown of the air multiplied by the permittivity of free space: