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mezya [45]
3 years ago
11

Technician A says that valve overlap is the number of crankshaft degrees that both valves are closed. Technician B says that val

ve overlap is the number of degrees that both valves are open. Who is​ right? A. Technician A only B. Technician B only C. Both technicians A and B D. Neither technician A nor B
Physics
1 answer:
8_murik_8 [283]3 years ago
3 0

Answer:

B. Technician B only

Explanation:

Technician A says that valve overlap is the number of crankshaft degrees that both valves are closed. Technician B says that valve overlap is the number of degrees that both valves are open. Who is​ right? A. Technician A only B. Technician B only C. Both technicians A and B D. Neither technician A nor B

Valve overlap is when  both the intake and exhaust valves are open. This occurs towards the end of the exhaust stroke, the intake valves are opened just before all the exhaust gases are released, providing more time for the intake air to enter the engine. Valve overlap must be shorter for a petrol/gasoline engine because the engine is drawing in fuel as well as air through the intake. ...it is not so for a sport car

the inlet valve and exhaust valve are located at the head of the engine. fuel enters the engine through the intake valve.

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The potential in a region of space due to a charge distribution is given by the expression V = ax2z + bxy − cz2 where a = −3.00
Elis [28]

Answer:

\vec{E} ( (0, -8.00 \ m, - 8.00 \ m) ) = (   48.00 \frac{V}{m}  ,  0  , - 144.00 \frac{V}{m}  )

Explanation:

We know that the relationship between the electric field \vec{E}(\vec{r}) and the potential V(\vec{r}) is given by

\vec{E} ( \vec{r}) = - \vec{\nabla} V(\vec{r})

So, for our potential:

V(r) = a x^2 z + b x y - c z^2

the electric field is :

\vec{E} ( \vec{r}) = - \vec{\nabla} ( a x^2 z + b x y - c z^2 )

\vec{E} ( \vec{r}) = - ( \frac{ \partial }{\partial x}, \frac{ \partial }{\partial y} , \frac{ \partial }{\partial z}) ( a x^2 z + b x y - c z^2 )

\vec{E} ( \vec{r}) = - ( \frac{ \partial }{\partial x} ( a x^2 z + b x y - c z^2 ) , \frac{ \partial }{\partial y}  ( a x^2 z + b x y - c z^2 ) , \frac{ \partial }{\partial z} ( a x^2 z + b x y - c z^2 ))

\vec{E} ( \vec{r}) = - ( 2 a x z + b y  , b x  , a x^2 - 2 c z )

This is the our electric field. At vector point

\vec{r} = (0, -8.00 \ m, - 8.00 \ m)

\vec{E} ( (0, -8.00 \ m, - 8.00 \ m) ) = - ( 2 a  * 0 * (-8.00 \ m)   + b (-8.00 \ m)   , b * 0  , a 0^2 - 2 c (-8.00 \ m)  )

\vec{E} ( (0, -8.00 \ m, - 8.00 \ m) ) = - ( 0   - b 8.00 \ m   ,  0  , 0 + 2 c 8.00 \ m  )

\vec{E} ( (0, -8.00 \ m, - 8.00 \ m) ) = (   b 8.00 \ m   ,  0  , - 2 c 8.00 \ m  )

Knowing

b= 6.00 \frac{V}{m^2}

and

c=9.00 \frac{V}{m^2}

the electric field is

\vec{E} ( (0, -8.00 \ m, - 8.00 \ m) ) = (   6.00 \frac{V}{m^2} * 8.00 \ m   ,  0  , - 9.00 \frac{V}{m^2} * 2* 8.00 \ m  )

\vec{E} ( (0, -8.00 \ m, - 8.00 \ m) ) = (   48.00 \frac{V}{m}  ,  0  , - 144.00 \frac{V}{m}  )

7 0
3 years ago
A pulley system with a mechanical advantage of 15 is used to lift a 1750 N piano to a third floor balcony that is 7 m above the
devlian [24]

Answer:

The  force is E = 117 \  N

Explanation:

From the question we are told that

     The  mechanical advantage is  ME =  15

     The load is L  =  1750 \  N

      The  height is  h  =  7  \  m

Generally mechanical advantage is mathematically represented as

       ME =  \frac{L }{E }

Here E is the force that must be applied to move the piano

=>     E =  \frac{L}{ ME }

=>     E =  \frac{1750 }{15  }

=>     E = 117 \  N

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lesya692 [45]

Answer:

X: Causes light rays to bend toward the principal axis

Y: Is capable of producing images that are smaller than objects

Z: Causes light rays to bend away from the principal axis

Explanation:

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Luba_88 [7]

Answer:

In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.

Explanation:

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