Question

The lamborghini murcielago can accelerate from 0 to 27.8 m/s (100 km/hr or 62.2 mi/hr) in a time of 3.40 seconds. Determine the acceleration of this car in both m/s/s and mi/hr/s. ( 8.18 m/s/s or 18 mi/hr/s)

Answer 1

To determine the acceleration of the car, we use equation of motion

$v = u +at$

Here, v is final velocity of the car, u is the initial velocity of the car, a is the acceleration of the car in time t.

Given, $v = 27.8 \ m/s$ , u=0 because car accelerate from 0 and t = 3.40 s.

Substituting these values in above equation, we get

$27.8 \ m/s = 0 + a \times 3.40 \ s \\\\ a= \frac{27 .8 m/s}{3.40\ s} = 8.17 \ m/s^2$

In mi/ h.s,

1 m = 0.000621371 mile.

1 s = (1/3600 ) hour =   0.000277778 hour.

Therefore,

$8.17 \ m/s^2 = 18.2757695061 \ mi/h.s (mile \ per \ hour \ second)$

Answer 2

- The lamborghini murcielago can accelerate from 0 to 27.8 m/s (100 km/hr or 62.2 mi/hr) in a time of ... The lamborghini murcielago can accelerate from 0 to 27.8 m/s (100 km/hr or 62.2 mi/hr) in a time of 3.40 seconds. Determine the acceleration of this car in both m/s/s and mi/hr/s. ( 8.18 m/s/s or 18 mi/hr/s).