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Goryan [66]
3 years ago
7

Use the dot product to find the magnitude of u if u = 6i - 3j

Physics
1 answer:
LuckyWell [14K]3 years ago
3 0
Vector u :
u = 6 i - 3 j
The magnitude of vector u :
| u | = \sqrt{6 ^{2}+(-3) ^{2}  } = \sqrt{36+9}= \\  \sqrt{45}= \sqrt{9*5}=3  \sqrt{5}
Answer:
The magnitude of vector u is 3√5. 
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