Draw the structure of the starting material in the ozonolysis reaction below. Hint: The starting material and product have the s
ame number of carbons (i.e., 1 mol reactant : 1 mol product).
2 answers:
<h3>Answer:</h3>
The starting material involved in the formation of 5-Oxoheptanal is 1-ethylcyclopent-1-ene as shown in reaction below.
<h3>Explanation:</h3>Ozone is one of the reactive allotrope of oxygen. It reacts vigorously with unsaturated compounds like alkenes and alkynes. In this reaction alkene and O₃ first react to produce Molozonide which is highly unstable and rearranges to form a stable ozonide as shown in scheme attached below.
Furthermore, the ozonide on reduction is convertwed into ketones and aldehydes respectively.
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The chemical compound sodium sulfide has the formula Na2S. It is written as . It has a crystalline state. Na is followed by a two or 2. this indicates that the molecule has two of the specified element's atoms.
There is just one of these because there is no number following the S.
In all, this molecule consists of one sulfur atom and two sodium atoms.
A compound's chemical formula, which uses symbols for combining atoms, reveals the composition of the complex. We require the valency of the combining parts in order to write the formula.
The sodium sulfide chemical formula must be written down. So sodium and sulfur make up the two elements in the chemical. Sodium has a valency of +1, while sulfur has a +2.
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Answer:
II
Explanation:
We must have a good idea of the fact that there are two mechanisms that come into play when we are discussing about the addition of hydrogen halides to alkenes. The first is the ionic mechanism and the second is the radical mechanism.
The ionic mechanism is accounted for by the Markovnikov rule while the radical mechanism occurs in the presence of peroxides and is generally referred to as anti Markovnikov addition.
The intermediate in anti Markovnikov addition involves the most stable radical, in this case, it is a tertiary radical as shown in the images attached. The most stable radical is II hence it leads to the major product shown in the other image.
