All categories

3 years ago

What is gidds free energy

1 answer:

6 0

<span>The Gibbs free energy is the system at any moment in time is defined as the enthalpy of the system minus the product of the temperature times the entropy of the system.</span>

You might be interested in

If you place rice on top or a speaker, what will happen to the rice when you turn the speaker on?

Dovator [93]

Answer:

The rice will move

Explanation:

the sound vibration and waves will cause the rice to move

3 0

3 years ago

A gas at 29.4 kPa is cooled from a temperature of 75°C to a temperature of 25°C at constant volume. What is the new pressure of

kirill115 [55]

<span>To solve this we assume that the gas inside the balloon is an ideal </span>gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant volume pressure and number of moles of the gas the ratio of T and P is equal to some constant. At another set of condition, the constant is still the same. Calculations are as follows:

T1/P1 = T2/P2

P2 = T2 x P1 / T1

P2 = 25 x 29.4 / 75

P2 = 9.8 kPa

7 0

3 years ago

Read 2 more answers

A small container of perfume is opened in a classroom. Soon every student in the room smells the perfume. Explain this in terms

melamori03 [73]

Answer: possibly diffusion

Explanation:

all particles are in motion unless at a certain degree so they'd spread throughout the room diluting as they continue to spread out.

6 0

3 years ago

How much energy is required to raise the temperature of 10.6 grams of gaseous neon from

Alona [7]

Answer:

Approximately $1.95 \times 10^{2}\; \rm J$ .

Explanation:

Look up the specific heat of gaseous neon:

$c = 1.03 \; \rm J \cdot g^{-1} \cdot K^{-1}$ .

Calculate the required temperature change:

$\Delta T = (37.9 - 20.0)\; \rm K = 17.9\; \rm K$ .

Let $m$ denote the mass of a sample of specific heat $C$ . Energy required to raise the temperature of this sample by $\Delta T$ :

$Q = c \cdot m \cdot \Delta T$ .

For the neon gas in this question:

$c = 1.03\; \rm J \cdot g^{-1}\cdot K^{-1}$ .
$m = 10.6\; \rm g$ .
$\Delta T = (37.9 - 20.0)\; \rm K = 17.9\; \rm K$ .

Calculate the energy associated with this temperature change:

$\begin{aligned}Q &= c \cdot m \cdot \Delta T \\ &= 1.03\; \rm J \cdot g^{-1}\cdot K^{-1} \times 10.6\; \rm g \times 17.9\; \rm K \\ &\approx 1.95 \times 10^{2}\; \rm J\end{aligned}$ .

3 0

3 years ago

Why do Hurricanes not form directly on the equator?

Gemiola [76]

They do form directly on the equators

8 0

3 years ago