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morpeh [17]
3 years ago
9

A ball is rolled twice across the same level laboratory table and allowed to roll off the table and strike the floor. In each tr

ial, the time it takes the ball to travel from the edge of the table to the floor is accurately measured. [Neglect friction.]
In trial B, the ball is traveling at 5.00 meters per second when it reaches the edge of the table. Compare the time it took the ball to reach the floor in trial B to the time it took the ball to reach the floor in trial A
Physics
1 answer:
schepotkina [342]3 years ago
5 0
By definition we know that the distance is equal to the speed by time
 d = v * t
 Clearing the time we have
 t = d / v
 for conservation of energy. we have to for every attempt
 mgh = (1/2) mv ^ 2
 Clearing the speed
 v = Root (2gh)
 Then, substituting
 t = d / v
 t = h / (Root (2gh)
 We conclude that the time is the same since it depends on the height of the table to the floor.
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The drawing shows three identical springs hanging from the ceiling. Nothing is attached to the first spring, whereas a 4.5 n blo
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<Continuation of the question>

(a) the spring constant (in N/m) and

(b) the weight of the block hanging from the third spring.

the distance for the first spring is 20cm, the second 35cm, the third 50cm.

Answer:

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