The force the horse and the rider exerts on the wall is equal to the weight combined acting in the opposite direction:
<h3>Force</h3>
Given Data
- mass of horse and rider = 575kg
- Force acting on wall = ??
When a body of mass rests on a surface, it exerts a force equal to the weight of the mass but opposite in direct on the mass/object
hence the force is computed as
Force = mass * acceleration
Force = 575 * 9.81
Force = 5640.75N
Learn more about force here:
brainly.com/question/12970081
I think the question meant to say net force on the box. Since force is a vector, the direction matters. 20N left is negated completely by the 50N right, which means the net force is 50N-20N to the right, 30N.
Before going to solve this question first we have to understand specific heat capacity of a substance .
The specific heat of a substance is defined as amount of heat required to raise the temperature of 1 gram of substance through one degree Celsius. Let us consider a substance whose mass is m.Let Q amount of heat is given to it as a result of which its temperature is raised from T to T'.
Hence specific heat of a substance is calculated as-
![c= \frac{Q}{m[T'-T]}](https://tex.z-dn.net/?f=c%3D%20%5Cfrac%7BQ%7D%7Bm%5BT%27-T%5D%7D)
Here c is the specific heat capacity.
The substance whose specific heat capacity is more will take more time to be heated up to a certain temperature as compared to a substance having low specific heat which is to be heated up to the same temperature.
As per the question John is experimenting on sand and water.Between sand and water,water has the specific heat 1 cal/gram per degree centigrade which is larger as compared to sand.Hence sand will be heated faster as compared to water.The substance which is heated faster will also cools faster.
From this experiment John concludes that water has more specific heat as compared to sand.
Answer:
given,
mass of the skier = 70.1 Kg
angle with horizontal, θ = 8.6°
magnitude of the force,F = ?
a) Applying newton's second law
velocity is constant, a = 0



b) now, when acceleration, a = 0.135 m/s²
velocity is constant, a = 0.135 m/s₂


