Ora serrate is located at the front edge
of the retina and has a tooth like appearance.
Our eye has many portions and parts, all
of them are there for some function. The ora
serrata is the most
anterior extent of the retina or serrated junction between the retina
and the ciliary body. The retina ends at the ora serrata, where the
ciliary body begins.
Answer:
Explanation:
constant speed is where the speed is the same throughout and instantaneous speed is speed given at any moment and average speed is a total distance traveled divided by the amount of time it took to travel it.
Given Information:
Mass = m = 20000 kg
Height of ramp = h = 0.840 m
Length of ramp = L = 20 m
Required Information:
Uphill Force = F = ?
Answer:
F = 8232 N
Explanation:
The force can be found using the equation
F = mgsinθ
Where m is the mass of block, g is the acceleration due to gravity
Since the ramp can be modeled as an inclined plane so it can formed into a triangle, recall that in right angle triangle sinθ is equal to opposite over hypotenuse. The opposite is the height and hypotenuse is the ramp surface.
sinθ = h/L = 0.840/20 = 0.042
F = 20000*9.8*0.042
F = 8232 N
Therefore, an uphill force of 8232 N would be needed.
Answer:
See below
Explanation:
Net force acting on the plane after overcoming frictional forces is
2.7 x 10^6 - 6.8 x 10^4 - 8.5 x 10^5 = 1 782 000 N
Work = F x d
= 1 782 000 x 1400 m = 2.5 x 10^9 J or 2.5 x 10^6 kJ
Answer:
A)0.00966 N/C
B) counterclockwise direction
Explanation:
We are given;
Diameter of the metal ring; d = 4.3 cm
Radius;r = 2.15 cm = 0.021- m
Initial magnetic field, B = 1.12 T
Rate of decrease of the magnetic field;dB/dt = 0.23 T/s
Now, as a result of change in magnetic field, an emf will be induced in it. Thus, , electric field is induced and given by the formula :
∫E•dr = d/dt∫B.A •dA
This gives;
E(2πr) = dB/dt(πr²)
Gives;. 2E = dB/dt(r)
E = dB/dt × 2r
We are given;
E = 0.23 × 2(0.021)
E = 0.00966 N/C
The magnitude of the electric field induced in the ring has a magnitude of 0.00966 N/C
B) The direction of electric field will be in a counterclock wise direction when viewed by someone on the south pole of the magnet
