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2 years ago

Carbon dioxide can be represented by the chemical formula

Chemistry

2 answers:

dangina [55]2 years ago

7 0

Answer: The chemical formula of carbon dioxide is $CO_2$

Explanation:

Chemical formula of any compound is the representation when elements combine with each other.

Carbon dioxide is a covalent compound and covalent compound is formed by the sharing of electrons between two elements that form a bond.

Electronic configuration of carbon: $1s^22s^22p^2$

Carbon need 4 electrons to complete its octet.

Electronic configuration of oxygen: $1s^22s^22p^4$

Oxygen need 2 electrons to complete its octet.

Hence, 2 oxygen atoms are required to complete the octet of 1 carbon atom. Hence, form a compound carbon dioxide $(CO_2)$

Pavel [41]2 years ago

7 0

Carbon dioxide is represented as 'CO2' by the chemical formula.

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Which molecule has a high specific heat?<br><br> a) C2H6<br> b) C2H6O<br> c) H2O

dem82 [27]

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2 years ago

Classify each of the coordination compounds according to the coordination number.

amid [387]

Coordination number has to do with the number of ligands that is attched to the central metal atom/ion.

<h3>What is coordination number?</h3>

The term coordination number has to do with the number of ligands that is attched to the central metal atom/ion. The coordination sphere contains this central metal along with associated ligands.

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1 year ago

Which isotope will spontaneously decay and emit particles with a charge of +2?

VikaD [51]

Answer: The correct option is 4.

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1) Alpha decay: It is a decay process in which alpha particle is released which has has a mass number of 4 and a charge of +2.

$_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_2^4\alpha$

2) Beta-minus decay: It is a decay in which a beta particle is released. The beta particle released has a mass number of 0 and a charge of (-1).

$_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta$

3) Beta-plus decay: It is a decay process in which a positron is released. The positron released has a mass number of 0 and has a charge of +1.

$_Z^A\textrm{X}\rightarrow _{Z-1}^A\textrm{Y}+_{+1}^0\beta$

For the given options:

Option 1: This nuclei will undergo beta-plus decay process to form $_{25}^{53}\textrm{Mn}$

$_{26}^{53}\textrm{Fe}\rightarrow _{25}^{53}\textrm{Mn}+_{+1}^0\beta$

Option 2: This nuclei will undergo beta-minus decay process to form $_{80}^{198}\textrm{Hg}$

$_{79}^{198}\textrm{Au}\rightarrow _{80}^{198}\textrm{Hg}+_{-1}^0\beta$

Option 3: This nuclei will undergo a beta minus decay process to form $_{56}^{137}\textrm{Ba}$

$_{55}^{137}\textrm{Cs}\rightarrow _{56}^{137}\textrm{Ba}+_{-1}^0\beta$

Option 4: This nuclei will undergo an alpha decay process to form $_{85}^{216}\textrm{At}$

$_{87}^{220}\textrm{Fr}\rightarrow _{85}^{216}\textrm{At}+_2^4\alpha$

Hence, the correct option is 4.

7 0

3 years ago

Read 2 more answers

A chemist adds 0.50L of a 0.485 M copper(II) sulfate CuSO4 solution to a reaction flask. Calculate the millimoles of copper(II)

den301095 [7]

Explanation:

It is given that volume is 0.50 L and molarity is 0.485 M. Hence, number of millimoles will be calculated as follows.

Number of millimoles = Molarity × Volume

As there are 1000 mL in 1 L. So, 0.50 L equals 500 mL.

Therefore, putting the given values into the above formula as follows.

Number of millimoles = Molarity × Volume

= 0.485 M × 500 mL

= 242.5

Thus, we can conclude that 242.5 millimoles of copper(II) sulfate has been added by the chemist to the flask.

4 0

3 years ago