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makkiz [27]
2 years ago
10

Describe what happens on the molecular level when acetic acid dissolves in water.

Chemistry
1 answer:
kompoz [17]2 years ago
3 0

Since most acetic acid molecules do not dissociate when a sample is dissolved in water, acetic acid and water molecule interactions are what determine how soluble a substance is. In its liquid state, water forms a network of hydrogen bonds among its molecules; when a material dissolves in water, this network of hydrogen bonds is broken.

<h3>What is acetic acid such a poor electrolyte?</h3>

Since acetic acid is a weak acid, only a small portion of the acetic acid molecules react to produce ethanoate and hydronium ions, shifting the equilibrium position substantially to the left. Aqueous acetic acid is a weak electrolyte as a result of the existence of these few ions.

<h3>Why does acetic acid have a low conductivity?</h3>

The majority ($> 99%) of the acetic acid molecules remain after dissolution, with only a very tiny portion deprotonating to form acetate anions. Only the latter are charged compounds, and as a result, only these increase the conductivity of the solution. They are few, and conductivity is low.

<h3>What makes acetic acid more potent than water?</h3>

The equilibrium shifts to the left and the concentration of hydrogen ions decreases when a strong acid is added to the buffer solution. A strong base is also added, which causes the equilibrium to move to the left and results in a smaller pH increase. Because of this, acetic acid is a better buffer than water.

Learn more about Acetic acid

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What volume of carbon dioxide is produced when 6.40 g of methane gas, CH4 (g), reacts with excess oxygen? All gases are at 35.0C
Mandarinka [93]

Answer:

V = 10.3 L

Explanation:

Given data:

Mass of methane = 6.40 g

Volume of CO₂ produced = ?

Temperature = 35°C (35+273 = 308 K)

Pressure = 100.0 KPa (100.0/101 = 0.98 atm)

Solution:

Chemical equation:

CH₄ +  2O₂        →       CO₂ + 2H₂O

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Number of moles = mass/molar mass

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Number of moles = 0.4 mol

Now we will compare the moles of CO₂ with CH₄.

         CH₄          :         CO₂

           1             :           1

        0.4            :         0.4

Volume of CO₂:

Formula:

PV = nRT

0.98 atm ×V = 0.4 mol ×0.0821 atm.L/mol.K ×  308 K

0.98 atm ×V = 10.11 atm.L

V = 10.11 atm.L /0.98 atm

V = 10.3 L

3 0
3 years ago
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