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Ira Lisetskai [31]
3 years ago
15

A soap bubble is essentially a thin film of water surrounded by air. The colors you see in soap bubbles are produced by interfer

ence. What visible wavelengths of light are strongly reflected from a 390-nm-thick soap bubble? What color would such a soap bubble appear to be?
Physics
1 answer:
drek231 [11]3 years ago
6 0

Answer:

Violet

Explanation:

Wavelength spectrum of visible light for the range of 390nm to 460nm is seen as violet. So the violet colour will be seen and reflected as what the eyes will see

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Object A of mass 0.70 kg travels horizontally on a frictionless surface at 20 m/s. It collides with object B, which is initially
AnnZ [28]

Answer:

25.71 kgm/s

Explanation:

Let K₁ and K₂ be the initial and final kinetic energies of object A and v₁ and v₂ its initial and final speeds.

Given that K₂ = 0.7K₁

1/2mv₂² = 0.7(1/2mv₁²)

v₂ = √0.7v₁ = √0.7 × 20 m/s = ±16.73 m/s

Since A rebounds, its velocity = -16.73 m/s and its momentum change, p₂ = mΔv = m(v₂ - v₁) = 0.7 kg (-16.73 - 20) m/s = 0.7( -36.73) = -25.71 kgm/s.

Th magnitude of object A's momentum change is thus 25.71 kgm/s

6 0
3 years ago
The greatest speed recorded by a baseball thrown by a pitcher was 162.3 km / h, obtained by Nolan Ryan in 1974. If the ball leav
Pepsi [2]

Answer:

0.96 m

Explanation:

First, convert km/h to m/s.

162.3 km/h × (1000 m/km) × (1 hr / 3600 s) = 45.08 m/s

Now find the time it takes to move 20 m horizontally.

Δx = v₀ t + ½ at²

20 m = (45.08 m/s) t + ½ (0 m/s²) t²

t = 0.4436 s

Finally, find how far the ball falls in that time.

Δy = v₀ t + ½ at²

Δy = (0 m/s) (0.4436 s) + ½ (-9.8 m/s²) (0.4436 s)²

Δy = -0.96 m

The ball will have fallen 0.96 meters.

3 0
4 years ago
Kinetic friction acts on a baseball player sliding into first base. Will the player's velocity change?
Law Incorporation [45]
Yes, his velocity will decrease the further he slides.
7 0
3 years ago
I need the science answer step by step
sukhopar [10]
What is the question
7 0
3 years ago
A train has an acceleration of magnitude 0.90 m/s2 while stopping. A pendulum with a 0.55-kg bob is attached to a ceiling of one
anygoal [31]

The angle of the pendulum with the vertical is 5.2^{\circ}

Explanation:

As the train decelerates, the bob of the pendulum will feel a force given by

F=ma

where

m = 0.55 kg is the mass of the bob

a=0.9 m/s^2 is the magnitude of the acceleration

In the horizontal direction.

The pendulum will be inclined at an angle \theta from the vertical, so it will be in equilibrium, and therefore the horizontal component of the tension in the string must be equal to the net force F of the previous equation:

T sin \theta = ma (1)

where T is the tension in the string.

We also know that the bob is in equilibrium along the vertical direction: so the vertical component of the tension must be equal to the weight of the bob,

T cos \theta = mg (2)

where g=9.8 m/s^2 is the acceleration of gravity.

Dividing eq.(1) by eq(2), we get:

tan \theta = \frac{a}{g}

And therefore, we find the angle:

\theta=tan^{-1}(\frac{a}{g})=tan^{-1}(\frac{0.90}{9.8})=5.2^{\circ}

Learn more about forces and acceleration:

brainly.com/question/11411375

brainly.com/question/1971321

brainly.com/question/2286502

brainly.com/question/2562700

#LearnwithBrainly

3 0
3 years ago
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