V = ( 2.44 x 10⁻² ) x ( 1.4 x 10⁻³ ) x ( 8.4 x 10⁻³ )
V = 2.9 x 10⁻⁷ m³
hope this helps!
The formula you need is: heat= specific heat x mass x ΔT
specific heat= 0.46 j/g-C
mass= 100.0 grams
ΔT= 40.2 - 15.0= 25.2C
heat= (0.46) x (100.0) x (25.2)= 1159.2 joules or 1200 joules (rounded off)
The volume of one mole of substance is 22.4 L
Answer : The heat of reaction for the process is, 1374.7 kJ
Explanation :
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The main chemical reaction is,
The intermediate balanced chemical reaction will be,
(1)
(2)
(3)
We reversing reaction 1, 3 and multiplying reaction 2 by 2 and then adding all the equations, we get :
(1)
(2)
(3)
The expression for heat of reaction for the process is:
Therefore, the heat of reaction for the process is, 1374.7 kJ
The ability to be crushed is a physical property and therefore is the answer.