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arlik [135]
3 years ago
9

Determine the maximum mass of the crate so

Engineering
1 answer:
Tpy6a [65]3 years ago
7 0

Answer:

293 kg

Explanation:

Let's say the tension in each cable is Tb, Tc, and Td.

First, find the length of cable AD:

r = √(2² + 2² + 1²)

r = 3

Using similar triangles:

Tdx = 2/3 Td

Tdy = 2/3 Td

Tdz = 1/3 Td

Sum of the forces in the x direction:

∑F = ma

Tb − 2/3 Td = 0

Td = 3/2 Tb

Sum of the forces in the y direction:

∑F = ma

2/3 Td − Tc = 0

Td = 3/2 Tc

Sum of the forces in the z direction:

∑F = ma

1/3 Td − mg = 0

Td = 3mg

From the first two equations, we know Td is greater than Tb or Tc.  So we need to set Td to 8.6 kN, or 8600 N.

8600 N = 3mg

m = 8600 N / (3 × 9.8 m/s²)

m ≈ 292.5 kg

Rounded to three significant figures, the maximum mass of the crate is 293 kg.

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An automated transfer line is to be designed. Based on previous experience, the average downtime per occurrence = 5.0 min, and t
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Answer:

a) 28 stations

b) Rp = 21.43

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Explanation:

Given:

Average downtime per occurrence = 5.0 min

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The optimum number of stations on the line that will maximize production rate is 28 stations.

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A uniform edge load of 500 lb/in. and 350 lb/in. is applied to the polystyrene specimen. If it is originally square and has dime
aliya0001 [1]

The image of the load applied to the polystyrene is missing, so i have attached it.

Answer:

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b_new = 2.00552

Explanation:

From the image attached, we can see that the load of 500 lb/in is applied in the x-direction while the load of 350 lb/in acts in the y-direction.

Now, formula for stress is;

Stress(σ) = Force/Area

We are not given force and area but the load and plate thickness.

Thus, stress = load/thickness

We are given;

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Load in y - direction = 350 lb/in.

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We are given v_p = 0.25 and Ep = 597 × 10³ psi

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