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Anna [14]
2 years ago
14

Estimate the endurance strength, Se, of a 37.5-mm- diameter rod of AISI 1040 steel having a machined finish and heat-treated to

a tensile strength of 760 MPa.
Engineering
1 answer:
7nadin3 [17]2 years ago
4 0

Answer:

endurance length is 236.64 MPa

Explanation:

data given:

d = 37.5 mm

Sut = 760MPa

endurance limit is

Se = 0.5 Sut

   = 0.5*760 = 380 MPa

surface factor is

Ka = a*Sut^b

where

Sut is ultimate strength

for AISI 1040 STEEL

a = 4.51, b = -0.265

Ka = 4.51*380^{-0.265}

Ka = 0.93

size factor is given as

Kb =1.29 d^{-0.17}

Kb = 0.669

Se = Sut *Ka*Kb

    = 380*0.669*0.93

Se = 236.64 MPa

therefore endurance length is 236.64 MPa

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Answer:

0.5m^2/Vs and 0.14m^2/Vs

Explanation:

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e= charge of electron

n= number of electrons

p= number of holes

\mu_e= mobility of electron

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Making the substitution in (S)

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8.9*10^4=(8.7*10^{23}*(-1.602*10^{-19})*\mu_e)+(8.7*10^{23}*(-1.602*10^{-19})*\mu_h)

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Mobility of hole in (S)

2.3*10^5 = (7.6*10^{22}*(-1.602*10^{-19})*\mu_e)+(1*10^{25}*(-1.602*10^{-19}*\mu_h))

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Then, solving the equation:

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An asphalt concrete mixture includes 94% aggregate by weight. The specific gravities of aggregate and asphalt are 2.65 and 1.0,
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Answer:

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= (147lb/ft³)(1ft³)

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Percentage weight of asphalt in<u> mix:</u>

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<u>The percentage of void in total mix:</u>

VTM = (0.02ft³/1ft³)100

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8 0
2 years ago
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