Answer:
28 , 24-inch screwdrivers
Explanation:
The total number of screwdrivers that can be purchased is = 70
4 - inch length screwdrivers = 10
6- inch length screwdrivers = 12
8- inch length screwdrivers = 20
Total = 20 +12 +10 = 42
Remaining = 70-42 = 28
So, heavy 24-inch screwdrivers = 28
Answer:
a)
, b)
, c) 
Explanation:
A turbine is a steady-state devices which transforms fluid energy into mechanical energy and is modelled after the Principle of Mass Conservation and First Law of Thermodynamics, whose expressions are described hereafter:
Mass Balance

Energy Balance

Specific volumes and enthalpies are obtained from property tables for steam:
Inlet (Superheated Steam)


Outlet (Liquid-Vapor Mix)


a) The mass flow rate of the steam is:



b) The exit velocity of steam is:




c) The power output of the steam turbine is:



Answer:
hi
Explanation:
the answer would be I dont know
- The conversion of 47,000 Ohms to kilo-ohms is equal to 47 kilo-ohms.
- The conversion of 47,000 Ohms to mega-ohms is equal to 0.047 kilo-ohms.
<h3>What is
resistance?</h3>
Resistance can be defined as an opposition to the flow of current in an electric circuit. Also, the standard unit of measurement of the resistance of an electric component is Ohms, which can be converted to kilo-ohms or mega-ohms.
For Ohms to kilo-ohms, we have:
1 Ohms = 0.001 kilo-ohms
47,000 Ohms = X kilo-ohms
Cross-multiplying, we have:
X = 0.001 × 47000
X = 47 kilo-ohms.
For Ohms to mega-ohms, we have:
1,000,000 ohms = 1 mega-ohms
47,000 Ohms = X mega-ohms
Cross-multiplying, we have:
X1,000,000 = 47,000
X = 47,000/1,000,000
X = 0.047 kilo-ohms.
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Answer:
q = 1.73 W
Explanation:
given data
small end = 5 cm
large end = 10 cm
high = 15 cm
small end is held = 600 K
large end at = 300 K
thermal conductivity of asbestos = 0.173 W/mK
solution
first we will get here side of cross section that is express as
...............1
here x is distance from small end and S1 is side of square at small end
and S2 is side of square of large end and L is length
put here value and we get
S = 5 +
S =
m
and
now we get here Area of section at distance x is
area A = S² ...............2
area A =
m²
and
now we take here small length dx and temperature difference is dt
so as per fourier law
heat conduction is express as
heat conduction q =
...............3
put here value and we get
heat conduction q =
it will be express as
now we intergrate it with limit 0 to 0.15 and take temp 600 to 300 K
solve it and we get
q (30) = (0.173) × (600 - 300)
q = 1.73 W