By analyzing the vector, the clothesline tension is 25 N.
We need to know about vectors to solve this problem. Force is included in vectors that have magnitude and direction. It can be written as
F = (Fx i + Fy j) N
where F is the force vector, Fx is the x-axis component and Fy is the y-axis component.
From the question we know that :
x = 10 m
(midpoint = 5m)
y = 1 m
m = 1 kg
Find the weight
W = m . g
W = 1 x 10
W = 10N
There are two y-axis components of the tension that hold the clothes. Because of static conditions, we can write
∑Fy = 0
Ty + Ty - W = 0
2Ty - 10 = 0
2Tsinθ - 10 = 0
Find sinθ
sinθ = y/x
sinθ = 1/5
Substitute the sinθ
2Tsinθ - 10 = 0
2T(1/5) - 10 = 0
2T/5 = 10
T = 25 N
Hence, the clothesline tension is 25 N.
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Answer:
4.545454 seconds
Explanation:
1500/330=4.545454 seconds
Answer:
is the minimum depth of snow for survivable stopping.
Explanation:
Given:
- terminal velocity of fall,

- mass of the paratrooper,

- force on the paratrooper by the ice to stop him,

<u>Firstly, we calculate the deceleration caused in the snow:</u>



Now, using equation of motion:
....................(1)
where:
v = final velocity of the body after stopping
u = initial velocity of the body just before hitting the snow
a = acceleration of the body in the snow
s = distance through in the snow
Putting respective values in eq. (1)


Answer:
Beta 17,000K, bc warmer is more blue
We will start from the definition of power in terms of the Force. Power could be described as the change of energy in an instant of time. Considering that Energy is the product between the Force and the distance traveled we would arrive at the expression


Here,
F = Force
h = Height
t = Time
As there is no external force, apart from the force of gravity, and this, is constant during the course of the object we will also have to be constant power and therefore this during its course will be the same. The correct answer is (1)