He loses 720 J for every metre he descends
![\texttt{ }](https://tex.z-dn.net/?f=%5Ctexttt%7B%20%7D)
<h3>Further explanation</h3>
<em>Let's recall </em><em>Kinetic Energy</em><em> Formula as follows:</em>
![\boxed{Ek = \frac{1}{2}mv^2}](https://tex.z-dn.net/?f=%5Cboxed%7BEk%20%3D%20%5Cfrac%7B1%7D%7B2%7Dmv%5E2%7D)
<em>Ek = Kinetic Energy ( Joule )</em>
<em>m = mass of the object ( kg )</em>
<em>v = speed of the object ( m/s )</em>
![\texttt{ }](https://tex.z-dn.net/?f=%5Ctexttt%7B%20%7D)
![\boxed{Ep = mgh}](https://tex.z-dn.net/?f=%5Cboxed%7BEp%20%3D%20mgh%7D)
<em>Ep = Potential Energy ( Joule )</em>
<em>m = mass of the object ( kg )</em>
<em>g = gravitational acceleration ( m/s² )</em>
<em>h = height position of the object ( m )</em>
Let us now tackle the problem !
![\texttt{ }](https://tex.z-dn.net/?f=%5Ctexttt%7B%20%7D)
<u>Given:</u>
mass = m = 72 kg
gravitational field strength = g = 10 N/kg
height = h = 1 m
<u>Asked:</u>
gravitational potential energy = Ep = ?
<u>Solution:</u>
<em>We will solve this problem as follows :</em>
![Ep = m g h](https://tex.z-dn.net/?f=Ep%20%3D%20m%20g%20h)
![Ep = 72 \times 10 \times 1](https://tex.z-dn.net/?f=Ep%20%3D%2072%20%5Ctimes%2010%20%5Ctimes%201)
![Ep = 720 \texttt{ J}](https://tex.z-dn.net/?f=Ep%20%3D%20720%20%5Ctexttt%7B%20J%7D)
![\texttt{ }](https://tex.z-dn.net/?f=%5Ctexttt%7B%20%7D)
<h3>Conclusion:</h3>
<em>He loses </em><em>720 J</em><em> for every metre he descends</em>
![\texttt{ }](https://tex.z-dn.net/?f=%5Ctexttt%7B%20%7D)
<h3>Learn more</h3>
![\texttt{ }](https://tex.z-dn.net/?f=%5Ctexttt%7B%20%7D)
<h3>Answer details</h3>
Grade: High School
Subject: Physics
Chapter: Energy