1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
wel
3 years ago
10

Essam is abseiling down a steep cliff. How much gravitational potential energy does he lose for every metre he descends? His mas

s is 72kg and the gravitational field strength is 10N/kg.

Physics
2 answers:
murzikaleks [220]3 years ago
8 0

He loses 720 J for every metre he descends

\texttt{ }

<h3>Further explanation</h3>

<em>Let's recall </em><em>Kinetic Energy</em><em> Formula as follows:</em>

\boxed{Ek = \frac{1}{2}mv^2}

<em>Ek = Kinetic Energy ( Joule )</em>

<em>m = mass of the object ( kg )</em>

<em>v = speed of the object ( m/s )</em>

\texttt{ }

\boxed{Ep = mgh}

<em>Ep = Potential Energy ( Joule )</em>

<em>m = mass of the object ( kg )</em>

<em>g = gravitational acceleration ( m/s² )</em>

<em>h = height position of the object ( m )</em>

Let us now tackle the problem !

\texttt{ }

<u>Given:</u>

mass = m = 72 kg

gravitational field strength = g = 10 N/kg

height = h = 1 m

<u>Asked:</u>

gravitational potential energy = Ep = ?

<u>Solution:</u>

<em>We will solve this problem as follows :</em>

Ep = m g h

Ep = 72 \times 10 \times 1

Ep = 720 \texttt{ J}

\texttt{ }

<h3>Conclusion:</h3>

<em>He loses </em><em>720 J</em><em> for every metre he descends</em>

\texttt{ }

<h3>Learn more</h3>
  • Impacts of Gravity : brainly.com/question/5330244
  • Effect of Earth’s Gravity on Objects : brainly.com/question/8844454
  • The Acceleration Due To Gravity : brainly.com/question/4189441
  • Newton's Law of Motion: brainly.com/question/10431582
  • Example of Newton's Law: brainly.com/question/498822

\texttt{ }

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Energy

Dafna11 [192]3 years ago
5 0

Answer:

720 J

Explanation:

The gravitational potential energy that Essam loses for every metre is given by:

\Delta U=mg \Delta h

where

m=72 kg is Essam's mass

g=10 N/kg is the gravitational field strength

\Delta h=1 m is the difference in height

By substituting the numbers into the formula, we find

\Delta U=(72 kg)(10 N/kg)(1 m)=720 J

You might be interested in
Gravity is an attractive force between two or more objects. The amount of force is directly proportional of the _______ of the o
Monica [59]
Blank 1: mass
Blank 2: distance
8 0
3 years ago
A wooden plaque is in the shape of an ellipse with height 30 centimeters and width 22 centimeters. Find an equation for the elli
Volgvan

Answer:

Explanation:

height of Ellipse =30 cm  

i.e. 2 a=30

Width of Ellipse =22 cm

i.e. 2 b=22

Equation of a vertical Ellipse is

\frac{x^2}{b^2}+\frac{y^2}{a^2}=1

a=15 ,b =11

\frac{x^2}{11^2}+\frac{y^2}{15^2}=1

at y=4 cm

\frac{x^2}{11^2}+\frac{4^2}{15^2}=1  

x=\frac{11}{15}\times \sqrt{15^2-4^2}

x=10.6 cm  

5 0
3 years ago
5. How much heat is generated when an
Mila [183]

Answer:

I HOPE THIS IS CORRECT

Explanation:

Power of water =2 kw=2000w

Mass of water =200kg

difference in temperature ΔT=70−10=60oC

Concept

energy required to heat the water = energy given by water in time t=pt

energy required to increase tempeature of water by 60oC,Q=msΔT

S= specific heat =4200J/kgoC

              pt=msΔT

   2000×t=200×4200×60

      t=25200  

or   t=25.2×103sec.

6 0
3 years ago
What are the assumptions on which the cosmological principle is based?.
prisoha [69]
Homogeneity and isotropy, On large enough scales, the Universe looks pretty much the same in all directions. The big bang theory is based on two assumptions: the first is centered around Einstein's general theory of relativity, which accurately describes gravity and the interactions of matter; and the second, also known as the cosmological principle, asserts that the universe is homogeneous and isotropic on a large enough scale.

Hope this helps!
Please give Brainliest!
4 0
2 years ago
A uniform plank of length 5.0 m and weight 225 N rests horizontally on two supports, with 1.1 m of the plank hanging over the ri
lawyer [7]

Answer:

x = 0.6034 m

Explanation:

Given

L = 5 m

Wplank = 225 N

Wman = 522 N

d = 1.1 m

x = ?

We have to take sum of torques about the right support point.  If the board is just about to tip, the normal force from the left support will be going to zero.  So the only torques come from the weight of the plank and the weight of the man.

∑τ = 0  ⇒     τ₁ + τ₂ = 0  

Torque come from the weight of the plank = τ₁

Torque come from the weight of the man = τ₂

⇒  τ₁ = + (5 - 1.1)*(225/5)*((5 - 1.1)/2) - (1.1)*(225/5)*((1.1)/2) = 315 N-m (counterclockwise)

⇒  τ₂ = Wman*x = 522 N*x   (clockwise)

then

τ₁ + τ₂ = (315 N-m) + (- 522 N*x) = 0

⇒  x = 0.6034 m

7 0
3 years ago
Other questions:
  • Write a message about an important aspect of life on earth to be sent beyond our solar system
    10·1 answer
  • How do amplitude and frequency affect light energy? help asap !!!!!!
    14·1 answer
  • A forklift raises a 1020 N crate 3.50 m up to a shelf l. How much work is done by the forklift on the crate? The forklift does J
    15·2 answers
  • 1. Study the map. What do you think divergent boundary means ? What about convergent boundary ?
    6·1 answer
  • Which statement describes why energy is released in a nuclear fission reaction based on mass-energy equivalence?
    14·1 answer
  • Max is helping his parents move to a new house. He picks up one box and is able to carry it into the house. He tries to pick up
    11·2 answers
  • Consider a stone and a football both at rest and having the same mass. why is it painful to kick the stone than to kick the foot
    8·1 answer
  • Can you help and explain these for me?
    9·1 answer
  • A car of mass 5000 kg was initially moving at 100 km/h and stops at a distance of 55 m. Find the
    15·1 answer
  • Determine the magnitude of the momentum of a ... 107-kg halfback moving eastward at 8 m/s.The halfback's momentum in kgm/s is:
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!