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algol13
4 years ago
14

An object is located 45.0 cm from a concave mirror. The focal length is 15.0

Physics
1 answer:
guajiro [1.7K]4 years ago
5 0

The image distance is 22.5 cm

Explanation:

We can solve the problem by using the mirror equation:

\frac{1}{f}=\frac{1}{p}+\frac{1}{q}

where

f is the forcal length

p is the distance of the object from the mirror

q is the distance of the image from the mirror

For this problem, we have:

f = +15.0 cm (focal length is positive  for a concave mirror)

p = 15.0 cm (distance of the object)

Therefore, solving  for the image distance, we find:

\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{15}-\frac{1}{45}=\frac{2}{45}\\\rightarrow q=\frac{45}{2}=22.5 cm

Learn more about reflection and other light phenomena:

brainly.com/question/3183125

brainly.com/question/12370040

#LearnwithBrainly

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The correct answer for the question that is being presented above is this one: "D.
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The complete question is;

"When is the force on a current-carrying wire in a magnetic field at its strongest?

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{\tt{\red{\underline{\underline{\huge{Answer:}}}}}}

\longrightarrow The rate of change of velocity per unit time is called acceleration.

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