As we can see here the lever has two forces at two ends
1. 300 N
2. 200 N
now we need to find the Torque on the lever about the fulcrum
so we will have
1. clockwise torque due to force at right end is
2. counterclockwise torque due to force at left end
so as per above calculations we can see that net torque on the lever is clockwise as it has more torque in clockwise direction
so <u>it will rotate clockwise</u>
Where are the answer from the choices ?
The force that must be exerted on the outside wheel to lift the anchor at constant speed is 6.925 x 10⁵ N.
<h3>Force exerted outside the wheel</h3>
The force exerted on the outside of the wheel can be determined by applying the principle of conservation of angular momentum as shown below.
∑τ = 0
- Let the distance traveled by the load = 1.5 m
- Let the radius of the wheel or position of the force = 0.45 m
∑τ = R(mg) - r(F)
rF = R(mg)
0.45F = 1.5(21,200 x 9.8)
F = 6.925 x 10⁵ N.
Thus, the force that must be exerted on the outside wheel to lift the anchor at constant speed is 6.925 x 10⁵ N.
Learn more about angular momentum here: brainly.com/question/7538238
