Which is considered a cation? A. H+ B. Cl- C. Ne D. He

Energy from the Sun contributes to these two main factors that create ocean currents: _____ and _____.

BigorU [14]

The sun also heats up the air in the atmosphere at the equator. This air will move towards the poles & cool over time. In the process, wind that occurs due to air currents will introduce currents at the surface of the ocean. Wind & Air

6 0

3 years ago

20. A substance with a high volatility A. has a high boiling point. B. tends to stay in the liquid or solid phase. C. readily ev

mestny [16]

According to this question, a substance with a high volatility readily evaporates.

<h3>What is volatility?</h3>

Volatility is the characteristics of a material which describes how readily the material undergo vaporization.

Volatile substances readily change phase from solid or liquid to gases via the process of vaporization.

Therefore, according to this question, a substance with a high volatility readily evaporates.

Learn more about volatility at: brainly.com/question/1603761

8 0

2 years ago

Draw both major organic product(s) that are obtained when 4-chloro-2-methyltoluene is treated with sodium amide followed by trea

victus00 [196]

Answer:

I attached the answer as an image. I also drew in the two most acidic hydrogens.

Explanation:

This goes through the 'benzyne' intermediate, meaning it does an E2-looking reaction by expelling a leaving group (chloride) from the adjacent part of the ring using the amide as a strong base. The triple-bonded benzyne has absurd bond angle strain, and is vulnerable to a good nucleophile like an amide ion, and the resultant sp2 anion is then reprotonated by the acid. I didn't draw in the acid-base reaction in step one, or the spectator ion (sodium).

5 0

3 years ago

How many moles is 55 g of Naci? 0.025 g of NaCO3?

mart [117]

Answer:

0.940mol &

0.000301mol respectively.

Explanation:

number of moles = given mass / molar mass

given mass of Nacl = 55g Molar mass = 23 + 35.5

n=m/M = 55g/58.5g/mol = 0.940mol

note- (add the atomic weights of sodium and chlorine to get the molar mass of Nacl.) = 58.5g/mol

similarly, NaCO3 = 23 + 12 + 16*3 = 83g/mol

n=m/M = 0.025g/83g/mol = 3.01 * 10^-4 = 0.000301mol

extra: If you ever get asked to put it in number of particles just use the relation of 1mole = 6.02 * 10^23 particles.

8 0

3 years ago

3. The molar volume of a gas at STP occupies 0 1 kilopascal O ooc 12 grams 22.4 L

Reil [10]

The molar volume of a gas at STP occupies 22.4 L.

Option D

Explanation:

To find the volume of 1 mole of a gas at STP, we use the Ideal Gas Law. It is the general gas equation which gives the relation to the measurable quantities to an ideal gas as below,

P (pressure) × V (volume) = n (number of moles) × R (the gas constant) × T (temperature in Kelvin)

STP = 1 atm of pressure and 273 K for temperature

P = 1 atm

V = ?

n = 1 mole

R = 0.0821 atm L/mol K

T = 273 K

Using the equation,

$\mathrm{PV}=\mathrm{nRT}$

$V=\frac{n R T}{P}$

By substituting the above values, in the equation,

$V=\frac{1 \times 0.082 \times 273}{1}=22.38\ L$

V = 22.38 L

8 0

3 years ago