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gulaghasi [49]
3 years ago
7

PLZ HELP ITS DUE IN 20 MINUTES, I WILL GIVE BRAINLIST TO RIGHT ANSWER

Chemistry
1 answer:
PolarNik [594]3 years ago
7 0
It’s A because those chemicals combines make 5.6 grams if you measure it.
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The bond dissociation energy to break 4 bond(s) in 1 mole of CH₄ molecules is:_____ **Any help would be greatly appreciated!**
frozen [14]

Answer:

The bond dissociation energy to break 4 bonds in 1 mol of CH is 1644 kJ

Explanation:

Since there are 4 C-H bonds in CH₄, the bond dissociation energy of 1 mol of CH₄ is 4 × bond dissociation energy of one C-H bond.

From the table one mole is C-H bond requires 411 kJ, that is 411 kJ/mol. Therefore, 4 C-H bonds would require 4 × 411 kJ = 1644 kJ

So, the bond dissociation energy to break 4 bonds in 1 mol of CH₄ is 1644 kJ

5 0
3 years ago
Edmentum
goldenfox [79]

Answer:

They all contain switches

6 0
2 years ago
Pressure of an ideal gas ___________________, when number of particles ( moles ) of gas decreases.
atroni [7]
The answer to your question is B.
3 0
3 years ago
What is the percent composition by mass of hydrogen in nh4hco3
Simora [160]

<u>Answer:</u> The percent composition by mass of hydrogen in given compound is 6.33 %

<u>Explanation:</u>

We are given:

A chemical compound having chemical formula of NH_4HCO_3

It is made up by the combination of 1 nitrogen atom, 5 hydrogen atoms, 1 carbon atom and 3 oxygen atoms

To calculate the percentage composition by mass of hydrogen in the compound, we use the equation:

\%\text{ composition of Hydrogen}=\frac{\text{Mass of hydrogen}}{\text{Mass of compound}}\times 100

Mass of compound = [(1\times 14)+(5\times 1)+(1\times 12)+(3\times 16)]=79g/mol

Mass of hydrogen = (5\times 1)=5g/mol

Putting values in above equation, we get:

\%\text{ composition of Hydrogen}=\frac{5g/mol}{79g/mol}\times 100=6.33\%

Hence, the percent composition by mass of hydrogen in given compound is 6.33 %

6 0
3 years ago
Consider the following intermediate reactions.
Alja [10]

2.1648 kg of CH4 will generate 119341 KJ of energy.

Explanation:

Write down the values given in the question

CH4(g) +2 O2 → CO2(g) +2 H20 (g)

ΔH1 = - 802 kJ

2 H2O(g)→2 H2O(I)

ΔH2= -88 kJ

The overall chemical reaction is

CH4 (g)+2 O2(g)→CO2(g)+2 H2O (I) ΔH2= -890 kJ

CH4 +2 O2 → CO2 +2 H20

(1mol)+(2mol)→(1mol+2mol)

Methane (CH4) = 16 gm/mol

oxygen (O2) =32 gm/mol

Here 1 mol CH4 ang 2mol of O2 gives 1mol of CO2 and 2 mol of 2 H2O

which generate 882 KJ /mol

Therefore to produce 119341 KJ of energy

119341/882 = 135.3 mol

to produce 119341 KJ of energy, 135.3 mol of CH4 and 270.6 mol of O2 will require

=135.3 *16

=2164.8 gm

=2.1648 kg of CH4

2.1648 kg of CH4 will generate 119341 KJ of energy

4 0
4 years ago
Read 2 more answers
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