Answer:
F' = F
Hence, the magnitude of the attractive force remains same.
Explanation:
The force of attraction between two bodies is given by Newton's Gravitational Law:
F = Gm₁m₂/r² --------------- equation 1
where,
F = Force of attraction between balls
G = Universal Gravitational Constant
m₁ = mass of first ball
m₂ = mass of 2nd ball
r = distance between balls
Now, we double the masses of both balls and the separation between them. So, the force of attraction becomes:
F' = Gm₁'m₂'/r'²
here,
m₁' = 2 m₁
m₂' = 2 m₂
r' = 2 r
Therefore,
F' = G(2 m₁)(2 m₂)/(2 r)²
F' = Gm₁m₂/r²
using equation 1:
<u>F' = F</u>
<u>Hence, the magnitude of the attractive force remains same.</u>
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Answer: Friction is the force resisting the relative motion of solid surfaces, fluid layers, and material elements sliding against each other. There are several types of friction: Dry friction is a force that opposes the relative lateral motion of two solid surfaces in contact
Answer:
Part a)
Time to reach the maximum height is given as
B)
Maximum height of the bullet is
C)
Horizontal range of the bullet is
Part d)
Final velocity of the bullet is v = 600 m/s at 30 degree
Explanation:
A) As we know that velocity of the bullet is
v = 600 m/s
So we have
Now time to reach the maximum height is given as
B) As we know that the object have zero final speed in y direction
C)
Now the horizontal displacement of the object in total time of flight is known as range of projectile
So we have
Part d)
As we know that the final height is same as that of initial So it will strike the ground at same velocity as that of initial velocity
So we have
v = 600 m/s at 30 degree