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gtnhenbr [62]
4 years ago
12

The force of attraction between any two objects is known as

Physics
2 answers:
Leona [35]4 years ago
7 0

Answer:

Gravity :)

Explanation:

lbvjy [14]4 years ago
3 0

Answer:

C-Gravity

Explanation:

Gravity is the The force of attraction between any two objects. For example throw a baseball in the air, What happens to it? It lands On the ground. This is gravity acting on the ball attracting it to the ground

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An objects speed is 2.40 m/s, and its momentum is 120.0 kg m/s. what is the mass of the object?
jarptica [38.1K]
Momentum is defined as 

P = m*v

where m is the mass of the object
and v is the speed of the object

We find m.............> m = P/v = 120 [kg.m/s] / 2.4 [m/s] = 50 kg

The mass is 50 kg
4 0
4 years ago
First, you will investigate purely vertical motion. The kinematics equation for vertical motion (ignoring air resistance) is giv
AlladinOne [14]

Answer: It takes 2.85 seconds.

Explanation: according to the question, the kinematics equation for vertical motion is

y(t) = y_{0} + v_{0} .t - \frac{1}{2} .gt^{2}

y₀ is the initial postion and equals 0 because it is fired at ground level;

v₀ is the initial speed and eqauls 14m/s;

g is gravity and it is 9.8m/s²;

y(t) is the final position and equals 0 because it is when the pumpkin hits the ground;

Rewriting the equation, we have:

0 + 14t - \frac{1}{2}.9.8.t^{2} = 0

14t - 4.9t² = 0

t(14 - 4.9t) = 0

For this equation to be zero,

t = 0 or

14 - 4.9t = 0

- 4.9t = - 14

t = \frac{14}{4.9}

t = 2.86

It takes 2.86 seconds for the pumpkin to hit the ground.

6 0
3 years ago
Who has the primary responsibility to prepare for emergencies?
Zolol [24]

Answer:

local government agencies

5 0
3 years ago
Estimate the order of magnitude of the length of a football field,
marissa [1.9K]

Answer:

d

Explanation:

6 0
3 years ago
Read 2 more answers
Two identical parallel plate capacitors A and B connected to a battery of V volts w/ the switch S closed. The switch is now open
Basile [38]
The electrostatic energy stored in a capacitor with capacitance C_0, with a voltage difference V applied to it, and without dielectric, is given by
U_0 =  \frac{1}{2} C_0 V^2
Now let's assume we fill the space between the two plates of the capacitor with a dielectric with constant k. The new capacitance of the capacitor is
C_k = k C_0
So, the energy stored now is
U_k =  \frac{1}{2}C_k V^2= \frac{1}{2}kC_0 V^2

Therefore, the ratio between the energies stored in the capacitor before and after the introduction of the dielectric is
\frac{U_k}{U_0}= \frac{ \frac{1}{2}kC_0 V^2 }{ \frac{1}{2} C_0 V^2}=  k
5 0
3 years ago
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